Difference between revisions of "2010 AMC 8 Problems/Problem 15"
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− | We do <math>100-30-20-15-10</math> to find the percent of gumdrops that are green. We find that <math>25%</math> of the gumdrops are green. That means there are <math>120</math> gumdrops. If we replace all blue gumdrops with green gumdrops, then <math>35%</math> of the jar's gumdrops are brown. <math> | + | We do <math>100-30-20-15-10</math> to find the percent of gumdrops that are green. We find that <math>25%</math> of the gumdrops are green. That means there are <math>120</math> gumdrops. If we replace all blue gumdrops with green gumdrops, then <math>35%</math> of the jar's gumdrops are brown. <math>\dfrac{35}{100} \cdot 120=42 \Rightarrow \boxed{\textbf{(C)}\ 42}</math> |
==See Also== | ==See Also== | ||
{{AMC8 box|year=2011|num-b=14|num-a=16}} | {{AMC8 box|year=2011|num-b=14|num-a=16}} |
Revision as of 19:51, 4 November 2012
Problem
A jar contains different colors of gumdrops. $30%$ (Error compiling LaTeX. Unknown error_msg) are blue, $20%$ (Error compiling LaTeX. Unknown error_msg) are brown, $15%$ (Error compiling LaTeX. Unknown error_msg) are red, $10%$ (Error compiling LaTeX. Unknown error_msg) are yellow, and other
gumdrops are green. If half of the blue gumdrops are replaced with brown gumdrops, how gumdrops will be brown?
Solution
We do to find the percent of gumdrops that are green. We find that $25%$ (Error compiling LaTeX. Unknown error_msg) of the gumdrops are green. That means there are
gumdrops. If we replace all blue gumdrops with green gumdrops, then $35%$ (Error compiling LaTeX. Unknown error_msg) of the jar's gumdrops are brown.
See Also
2011 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 14 |
Followed by Problem 16 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |