Difference between revisions of "2011 AMC 8 Problems/Problem 2"
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==Solution== | ==Solution== | ||
− | The area of a rectangle is given by the formula length times width. Karl's garden is <math>20 \times 45 = 900</math> square feet and Makenna's garden is <math>25 \times 40 = 1000</math> square feet. Since <math>1000 > 900,</math> Makenna's garden is larger by <math>1000-900=100</math> square feet. <math>\Rightarrow \boxed{\textbf{(E)}}</math> | + | The area of a rectangle is given by the formula length times width. Karl's garden is <math>20 \times 45 = 900</math> square feet and Makenna's garden is <math>25 \times 40 = 1000</math> square feet. Since <math>1000 > 900,</math> Makenna's garden is larger by <math>1000-900=100</math> square feet. <math>\Rightarrow \boxed{ \textbf{(E)}\ \text{Makenna's garden is larger by 100 square feet.} }</math> |
==See Also== | ==See Also== | ||
{{AMC8 box|year=2011|num-b=1|num-a=3}} | {{AMC8 box|year=2011|num-b=1|num-a=3}} |
Revision as of 08:18, 5 November 2012
Problem
Karl's rectangular vegetable garden is feet by
feet, and Makenna's is
feet by
feet. Whose garden is larger in area?
Solution
The area of a rectangle is given by the formula length times width. Karl's garden is square feet and Makenna's garden is
square feet. Since
Makenna's garden is larger by
square feet.
See Also
2011 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 3 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |