Difference between revisions of "1988 AHSME Problems/Problem 1"

Latest revision as of 00:42, 23 October 2014

$\sqrt{8}+\sqrt{18}=$

$\text{(A)}\ \sqrt{20}\qquad\text{(B)}\ 2(\sqrt{2}+\sqrt{3})\qquad\text{(C)}\ 7\qquad\text{(D)}\ 5\sqrt{2}\qquad\text{(E)}\ 2\sqrt{13}$

$\sqrt{8} = 2 \sqrt{2}$

$\sqrt{18} = 3 \sqrt{2}$

So adding the two terms we get $2 \sqrt{2} + 3 \sqrt{2} = 5 \sqrt{2}$ , which corresponds to answer choice $\boxed{\textbf{(D)}}$ .

1988 AHSME (Problems • Answer Key • Resources)
Preceded by First Question	Followed by Problem 2
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30
All AHSME Problems and Solutions

@@ Line 1: / Line 1: @@
+==Problem==
 <math> \sqrt{8}+\sqrt{18}= </math>
 <cmath> \text{(A)}\ \sqrt{20}\qquad\text{(B)}\ 2(\sqrt{2}+\sqrt{3})\qquad\text{(C)}\ 7\qquad\text{(D)}\ 5\sqrt{2}\qquad\text{(E)}\ 2\sqrt{13} </cmath>
-Solution:  <math> \sqrt{8} = 2 * \sqrt{2} </math>
+==Solution==
-               <math> \sqrt{18} = 3 * \sqrt{2} </math>
+<math> \sqrt{8} = 2  \sqrt{2} </math>
+<math> \sqrt{18} = 3  \sqrt{2} </math>
+So adding the two terms we get <math> 2  \sqrt{2} + 3  \sqrt{2} = 5  \sqrt{2} </math> , which corresponds to answer choice <math>\boxed{\textbf{(D)}}</math> .
+== See also ==
+{{AHSME box|year=1988|before=First Question|num-a=2}}
-So adding the two terms we get <math> 2 * \sqrt{2} + 3 * \sqrt{2} = 5 * \sqrt{2} </math> , which corresponds to answer choice \text{(D)} .
+[[Category: Introductory Algebra Problems]]
+{{MAA Notice}}