Difference between revisions of "1970 AHSME Problems/Problem 14"
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== Solution == | == Solution == | ||
| − | <math>\ | + | From the quadratic equation, the two roots of the equation are <math>\frac{-p\pm\sqrt{p^2-4q}}{2}</math>. The positive difference between these roots is <math>\sqrt{p^2 - 4q}</math>. Setting <math>\sqrt{p^2-4q}=1</math> and isolating <math>p</math> gives <math>\sqrt{4q+1}</math>, or choice <math>\boxed{\text{(A)}}</math>. |
== See also == | == See also == | ||
Latest revision as of 00:30, 24 February 2023
Problem
Consider 
, where 
and 
are positive numbers. If the roots of this equation differ by 1, then equals
Solution
From the quadratic equation, the two roots of the equation are 
. The positive difference between these roots is 
. Setting 
and isolating gives 
, or choice 
.
See also
| 1970 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 13 |
Followed by Problem 15 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
