Difference between revisions of "2018 AMC 8 Problems/Problem 3"

Latest revision as of 19:52, 13 June 2024

Problem

Students Arn, Bob, Cyd, Dan, Eve, and Fon are arranged in that order in a circle. They start counting: Arn first, then Bob, and so forth. When the number contains a 7 as a digit (such as 47) or is a multiple of 7 that person leaves the circle and the counting continues. Who is the last one present in the circle?

$\textbf{(A) } \text{Arn}\qquad\textbf{(B) }\text{Bob}\qquad\textbf{(C) }\text{Cyd}\qquad\textbf{(D) }\text{Dan}\qquad \textbf{(E) }\text{Eve}\qquad$

Solution 1(Simulation)

The five numbers which cause people to leave the circle are $7, 14, 17, 21,$ and $27.$

The most straightforward way to do this would be to draw out the circle with the people, and cross off people as you count.

Assuming the six people start with $1$ , Arn counts $7$ so he leaves first. Then, Cyd counts $14$ as there are $7$ numbers to be counted from this point. Then, Fon, Bob, and Eve, count, $17,$ $21,$ and $27$ , respectively, so the last one standing is Dan. Hence, the answer would be $\boxed{\textbf{(D) }\text{Dan}}$ .

~Nivaar

Solution 2

Assign each person a position: Arn is in position $1$ , Bob in $2$ , etc. Note that if there are $n$ people standing in a circle, a person will say a number that is congruent to their position modulo $n$ . It follows that if there are $k$ numbers to be said (with someone leaving on the $kth$ ), the person that leaves will stand in position $k\pmod{n}.$

The five numbers which cause people to leave the circle are $7, 14, 17, 21,$ and $27.$ Since there are initially $6$ people in the circle, so the person who leaves stands in position $7\equiv 1\pmod 6$ , or position $1$ .

Arn now leaves, and because Bob is the next person to say a number, we reassign the positions such that Bob is in position $1$ , Cyd in $2$ , and Fon in $5$ . There are $7$ more numbers to be said, and someone leaves on the $7th$ . It follows that the person who leaves stands in position $7\equiv 2\pmod 5$ .

Cyd leaves the circle, and $4$ people remain, namely Bob, Dan, Eve, and Fon. Assign the position numbers such that Dan has $1$ , Eve $2$ , etc. There are $3$ more numbers to be said, and someone leaves on the $3rd$ . The person standing in position $3$ (Fon) now leaves.

There are two people left, Eve and Dan, with Dan in position $1$ now. There are $6$ more numbers to be said, and Eve is standing in position $6\equiv 0\pmod 2$ , so she leaves.

The last person standing is $\boxed{\textbf{(D) }\text{Dan}}$ .

-Benedict T (countmath1) Why? Why would you do this?

Video Solution (CRITICAL THINKING!!!)

https://youtu.be/wziaWxZmjgg

~Education, the Study of Everything

Video Solution

https://youtu.be/uK4bbVpwHGc

~savannahsolver

@@ Line 2: / Line 2: @@
 Students Arn, Bob, Cyd, Dan, Eve, and Fon are arranged in that order in a circle. They start counting: Arn first, then Bob, and so forth. When the number contains a 7 as a digit (such as 47) or is a multiple of 7 that person leaves the circle and the counting continues. Who is the last one present in the circle?
-<math>\textbf{(A) } \text{Arn}\qquad\textbf{(B) }\text{Bob}\qquad\textbf{(C) }\text{Cyd}\qquad\textbf{(D) }\text{Dan}\qquad \textbf{(E) }\text{Eve}\qquad\textbf{(F) }\text{Fon}</math>
+<math>\textbf{(A) } \text{Arn}\qquad\textbf{(B) }\text{Bob}\qquad\textbf{(C) }\text{Cyd}\qquad\textbf{(D) }\text{Dan}\qquad \textbf{(E) }\text{Eve}\qquad</math>
-==Solution 1==
+==Solution 1(Simulation)==
 The five numbers which cause people to leave the circle are <math>7, 14, 17, 21,</math> and <math>27.</math>
 The most straightforward way to do this would be to draw out the circle with the people, and cross off people as you count.
-Assuming the six people start with <math>1</math>, Arn counts <math>7</math> so he leaves first. Then Cyd counts <math>14</math>, as there are <math>7</math> numbers to be counted from this point. Then Fon, Bob, and Eve, count, <math>17,</math> <math>21,</math> and <math>27</math> respectively, so last one standing is Dan. Hence, the answer would be <math>\boxed{\text{(D) Dan}}</math>.
+Assuming the six people start with <math>1</math>, Arn counts <math>7</math> so he leaves first. Then, Cyd counts <math>14</math> as there are <math>7</math> numbers to be counted from this point. Then, Fon, Bob, and Eve, count, <math>17,</math> <math>21,</math> and <math>27</math>, respectively, so the last one standing is Dan. Hence, the answer would be <math>\boxed{\textbf{(D) }\text{Dan}}</math>.
+~Nivaar
+==Solution 2==
+Assign each person a position: Arn is in position <math>1</math>, Bob in <math>2</math>, etc. Note that if there are <math>n</math> people standing in a circle, a person will say a number that is congruent to their position modulo <math>n</math>. It follows that if there are <math>k</math> numbers to be said (with someone leaving on the <math>kth</math>), the person that leaves will stand in position <math>k\pmod{n}.</math>
+The five numbers which cause people to leave the circle are <math>7, 14, 17, 21,</math> and <math>27.</math> Since there are initially <math>6</math> people in the circle, so the person who leaves stands in position <math>7\equiv 1\pmod 6</math>, or position <math>1</math>.
+Arn now leaves, and because Bob is the next person to say a number, we reassign the positions such that Bob is in position <math>1</math>, Cyd in <math>2</math>, and Fon in <math>5</math>. There are <math>7</math> more numbers to be said, and someone leaves on the <math>7th</math>. It follows that the person who leaves stands in position <math>7\equiv 2\pmod 5</math>.
+Cyd leaves the circle, and <math>4</math> people remain, namely Bob, Dan, Eve, and Fon. Assign the position numbers such that Dan has <math>1</math>, Eve <math>2</math>, etc. There are <math>3</math> more numbers to be said, and someone leaves on the <math>3rd</math>. The person standing in position <math>3</math> (Fon) now leaves.
+There are two people left, Eve and Dan, with Dan in position <math>1</math> now. There are <math>6</math> more numbers to be said, and Eve is standing in position <math>6\equiv 0\pmod 2</math>, so she leaves.
+The last person standing is <math>\boxed{\textbf{(D) }\text{Dan}}</math>.
+-Benedict T (countmath1)
+Why? Why would you do this?
+== Video Solution (CRITICAL THINKING!!!)==
+https://youtu.be/wziaWxZmjgg
+~Education, the Study of Everything
+==Video Solution==
+https://youtu.be/uK4bbVpwHGc
+~savannahsolver
 ==See Also==

2018 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 2	Followed by Problem 4
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

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