Difference between revisions of "2007 AMC 8 Problems/Problem 18"
m (Reverted edits by Raina0708 (talk) to last revision by Savannahsolver) (Tag: Rollback) |
Pi is 3.14 (talk | contribs) m |
||
(One intermediate revision by one other user not shown) | |||
Line 8: | Line 8: | ||
<math>\mathrm{(A)}\ 3 \qquad \mathrm{(B)}\ 5 \qquad \mathrm{(C)}\ 6 \qquad \mathrm{(D)}\ 8 \qquad \mathrm{(E)}\ 10</math> | <math>\mathrm{(A)}\ 3 \qquad \mathrm{(B)}\ 5 \qquad \mathrm{(C)}\ 6 \qquad \mathrm{(D)}\ 8 \qquad \mathrm{(E)}\ 10</math> | ||
− | |||
− | |||
− | |||
Line 21: | Line 18: | ||
Note that the ones and thousands digits are, added together, <math>8</math>. (and so on...) So the answer is <math>\boxed{\textbf{(D)}\ 8}</math> | Note that the ones and thousands digits are, added together, <math>8</math>. (and so on...) So the answer is <math>\boxed{\textbf{(D)}\ 8}</math> | ||
− | This is a direct | + | This is a direct multiplication way. |
+ | |||
+ | ==Video Solution by OmegaLearn== | ||
+ | https://youtu.be/7an5wU9Q5hk?t=2085 | ||
+ | |||
+ | ~ pi_is_3.14 | ||
==Video Solution by WhyMath== | ==Video Solution by WhyMath== |
Latest revision as of 04:43, 31 December 2022
Contents
[hide]Problem
The product of the two -digit numbers
and
has thousands digit and units digit . What is the sum of and ?
Solution
We can first make a small example to find out and . So,
The ones digit plus thousands digit is .
Note that the ones and thousands digits are, added together, . (and so on...) So the answer is This is a direct multiplication way.
Video Solution by OmegaLearn
https://youtu.be/7an5wU9Q5hk?t=2085
~ pi_is_3.14
Video Solution by WhyMath
~savannahsolver
See Also
2007 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 17 |
Followed by Problem 19 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.