Difference between revisions of "2022 AMC 8 Problems/Problem 14"
MRENTHUSIASM (talk | contribs) (Created page with "==Problem== In how many ways can the letters in <math>\textbf{BEEKEEPER}</math> be rearranged so that two or more <math>\textbf{E}</math>s do not appear together? <math>\tex...") |
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~MRENTHUSIASM | ~MRENTHUSIASM | ||
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+ | ==Video Solution by Math-X (First understand the problem!!!)== | ||
+ | https://youtu.be/oUEa7AjMF2A?si=sMxdry7U6U_2bPZH&t=2168 | ||
+ | |||
+ | ~Math-X | ||
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+ | ==Video Solution (CREATIVE THINKING!!!)== | ||
+ | https://youtu.be/419vsFnrGeY | ||
+ | |||
+ | ~Education, the Study of Everything | ||
+ | |||
+ | ==Video Solution== | ||
+ | https://youtu.be/Ij9pAy6tQSg?t=1222 | ||
+ | |||
+ | ~Interstigation | ||
+ | |||
+ | ==Video Solution== | ||
+ | https://youtu.be/p29Fe2dLGs8?t=212 | ||
+ | |||
+ | ~STEMbreezy | ||
+ | |||
+ | ==Video Solution== | ||
+ | https://youtu.be/NmfnoSn3CDg | ||
+ | |||
+ | ~savannahsolver | ||
+ | |||
+ | ==Video Solution== | ||
+ | https://youtu.be/c6shf8oma5c | ||
+ | |||
+ | ~harungurcan | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2022|num-b=13|num-a=15}} | {{AMC8 box|year=2022|num-b=13|num-a=15}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Latest revision as of 14:48, 23 November 2023
Contents
Problem
In how many ways can the letters in be rearranged so that two or more
s do not appear together?
Solution
All valid arrangements of the letters must be of the form
The problem is equivalent to counting the arrangements of
and
into the four blanks, in which there are
ways.
~MRENTHUSIASM
Video Solution by Math-X (First understand the problem!!!)
https://youtu.be/oUEa7AjMF2A?si=sMxdry7U6U_2bPZH&t=2168
~Math-X
Video Solution (CREATIVE THINKING!!!)
~Education, the Study of Everything
Video Solution
https://youtu.be/Ij9pAy6tQSg?t=1222
~Interstigation
Video Solution
https://youtu.be/p29Fe2dLGs8?t=212
~STEMbreezy
Video Solution
~savannahsolver
Video Solution
~harungurcan
See Also
2022 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 13 |
Followed by Problem 15 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.