Difference between revisions of "1996 AJHSME Problems/Problem 18"
Loving-math (talk | contribs) (→Problem) |
Speedcuber7 (talk | contribs) (→Solution) |
||
(6 intermediate revisions by 2 users not shown) | |||
Line 1: | Line 1: | ||
==Problem== | ==Problem== | ||
− | Ana's monthly salary was <math>\$2000</math> in May. In June she received a | + | Ana's monthly salary was <math>\$2000</math> in May. In June she received a 20% raise. In July she received a 20% pay cut. After the two changes in June and July, Ana's monthly salary was |
<math>\text{(A)}\ 1920\text{ dollars} \qquad \text{(B)}\ 1980\text{ dollars} \qquad \text{(C)}\ 2000\text{ dollars} \qquad \text{(D)}\ 2020\text{ dollars} \qquad \text{(E)}\ 2040\text{ dollars}</math> | <math>\text{(A)}\ 1920\text{ dollars} \qquad \text{(B)}\ 1980\text{ dollars} \qquad \text{(C)}\ 2000\text{ dollars} \qquad \text{(D)}\ 2020\text{ dollars} \qquad \text{(E)}\ 2040\text{ dollars}</math> | ||
Line 7: | Line 7: | ||
==Solution== | ==Solution== | ||
− | + | Notice that a 20% raise translates to Ana's monthly salary multiplied by <math>(100 + 10)\% = 120\%</math>, and a 20% pay cut translates to her salary multiplied by <math>100\% - 20\% = 80\%</math>, so | |
+ | |||
+ | |||
+ | <cmath>2000 \cdot 120\% = 2400</cmath> | ||
+ | <cmath>2400 \cdot 80\% = 1920 \rightarrow \boxed{\textbf{A}}</cmath> | ||
+ | |||
+ | ~SpeedCuber7 | ||
==See Also== | ==See Also== |
Latest revision as of 04:49, 27 July 2024
Problem
Ana's monthly salary was in May. In June she received a 20% raise. In July she received a 20% pay cut. After the two changes in June and July, Ana's monthly salary was
Solution
Notice that a 20% raise translates to Ana's monthly salary multiplied by , and a 20% pay cut translates to her salary multiplied by , so
~SpeedCuber7
See Also
1996 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 17 |
Followed by Problem 19 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.