Difference between revisions of "2020 AMC 12B Problems/Problem 2"
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<cmath>\frac{100^2-7^2}{70^2-11^2} \cdot \frac{(70-11)(70+11)}{(100-7)(100+7)} = \frac{(100-7)(100+7)}{(70-11)(70+11)} \cdot \frac{(70-11)(70+11)}{(100-7)(100+7)}.</cmath> | <cmath>\frac{100^2-7^2}{70^2-11^2} \cdot \frac{(70-11)(70+11)}{(100-7)(100+7)} = \frac{(100-7)(100+7)}{(70-11)(70+11)} \cdot \frac{(70-11)(70+11)}{(100-7)(100+7)}.</cmath> | ||
Cancelling all the terms, we get <math>\boxed{\textbf{(A) } 1}</math> as the answer. | Cancelling all the terms, we get <math>\boxed{\textbf{(A) } 1}</math> as the answer. | ||
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| + | == Video Solution (HOW TO CREATIVELY THINK!!!)== | ||
| + | https://youtu.be/2z8MaCeqIKs | ||
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| + | ~Education, the Study of Everything | ||
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== Video Solution == | == Video Solution == | ||
https://youtu.be/WfTty8Fe5Fo | https://youtu.be/WfTty8Fe5Fo | ||
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== See Also == | == See Also == | ||
{{AMC12 box|year=2020|ab=B|num-b=1|num-a=3}} | {{AMC12 box|year=2020|ab=B|num-b=1|num-a=3}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Latest revision as of 14:00, 8 June 2023
Contents
Problem
What is the value of the following expression?
![\[\frac{100^2-7^2}{70^2-11^2} \cdot \frac{(70-11)(70+11)}{(100-7)(100+7)}\]](http://latex.artofproblemsolving.com/5/f/4/5f4f7b3d646f920fd9ef3f767aad765860768b41.png)
Solution
Using difference of squares to factor the left term, we get
![\[\frac{100^2-7^2}{70^2-11^2} \cdot \frac{(70-11)(70+11)}{(100-7)(100+7)} = \frac{(100-7)(100+7)}{(70-11)(70+11)} \cdot \frac{(70-11)(70+11)}{(100-7)(100+7)}.\]](http://latex.artofproblemsolving.com/4/b/d/4bd5ad760781142ae19f9ab08f756ab9c74008f3.png)
Cancelling all the terms, we get 
as the answer.
Video Solution (HOW TO CREATIVELY THINK!!!)
~Education, the Study of Everything
Video Solution
See Also
| 2020 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 1 |
Followed by Problem 3 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
