Difference between revisions of "1995 AJHSME Problems/Problem 16"
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==Solution== | ==Solution== | ||
| − | Altogether, the summer project totaled <math>(7)(3)+(4)(5)+(5)(9)=21+20+45=86</math> days of work for a single student. This equals <math>744/86 = 9</math> dollars per day per student. The students from Balboa school earned <math>9(4)(5)=\boxed{\text{(C)}\ 180.00\ \text{dollars}}</math> | + | Altogether, the summer project totaled <math>(7)(3)+(4)(5)+(5)(9)=21+20+45=86</math> days of work for a single student. This equals <math>744/86 = 9</math> dollars per day per student rounded to the nearest dollar (744/86 ≈ 8.65). The students from Balboa school earned <math>9(4)(5)=\boxed{\text{(C)}\ 180.00\ \text{dollars}}</math> approximately. |
==See Also== | ==See Also== | ||
{{AJHSME box|year=1995|num-b=15|num-a=17}} | {{AJHSME box|year=1995|num-b=15|num-a=17}} | ||
Latest revision as of 23:08, 8 December 2024
Problem
Students from three middle schools worked on a summer project.
- Seven students from Allen school worked for
days. - Four students from Balboa school worked for
days. - Five students from Carver school worked for
days.
days.
days.
days.The total amount paid for the students' work was 744. Assuming each student received the same amount for a day's work, how much did the students from Balboa school earn altogether?
Solution
Altogether, the summer project totaled 
days of work for a single student. This equals 
dollars per day per student rounded to the nearest dollar (744/86 ≈ 8.65). The students from Balboa school earned 
approximately.
See Also
| 1995 AJHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 15 |
Followed by Problem 17 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
