1995 AJHSME Problems/Problem 6
Contents
[hide]Problem
Figures , , and are squares. The perimeter of is and the perimeter of is . The perimeter of is
Solution 1
Since the perimeter of , each side is .
Since the perimeter of is , each side is .
The side of is equal to the sum of the sides of and . Therefore, the side of is .
Since is also a square, it has an perimeter of , and the answer is .
Solution 2
Let a side of equal , and let a side of equal . The perimeter of is , and the perimeter of is . One side of has length , so the perimeter is , which just so happens to be the sum of the perimeters of and , giving us , or answer .
See Also
1995 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 5 |
Followed by Problem 7 | |
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