1995 AJHSME Problems/Problem 4

Problem

A teacher tells the class,

"Think of a number, add 1 to it, and double the result. Give the answer to your partner. Partner, subtract 1 from the number you are given and double the result to get your answer."

Ben thinks of $6$, and gives his answer to Sue. What should Sue's answer be?

$\text{(A)}\ 18 \qquad \text{(B)}\ 24 \qquad \text{(C)}\ 26 \qquad \text{(D)}\ 27 \qquad \text{(E)}\ 30$

Solution

Ben adds $1$ to $6$, getting $1 + 6 = 7$. Then Ben doubles it, to get $7\cdot 2 = 14$. He gives this number to Sue. Then Sue subtracts $1$ from the number, to get $14 - 1 = 13$. Finally, Sue doubles the result to get $13\cdot 2 = 26$, and the answer is $\boxed{C}$.

See Also

1995 AJHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 3
Followed by
Problem 5
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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