# 1995 AJHSME Problems/Problem 4

## Problem

A teacher tells the class,

"Think of a number, add 1 to it, and double the result. Give the answer to your partner. Partner, subtract 1 from the number you are given and double the result to get your answer."

Ben thinks of $6$, and gives his answer to Sue. What should Sue's answer be? $\text{(A)}\ 18 \qquad \text{(B)}\ 24 \qquad \text{(C)}\ 26 \qquad \text{(D)}\ 27 \qquad \text{(E)}\ 30$

## Solution

Ben adds $1$ to $6$, getting $1 + 6 = 7$. Then Ben doubles it, to get $7\cdot 2 = 14$. He gives this number to Sue. Then Sue subtracts $1$ from the number, to get $14 - 1 = 13$. Finally, Sue doubles the result to get $13\cdot 2 = 26$, and the answer is $\boxed{C}$.

## See Also

 1995 AJHSME (Problems • Answer Key • Resources) Preceded byProblem 3 Followed byProblem 5 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 All AJHSME/AMC 8 Problems and Solutions

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