Difference between revisions of "1998 AHSME Problems/Problem 12"

 
 
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#REDIRECT [[1998 AHSME]]
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== Problem ==
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How many different prime numbers are factors of <math>N</math> if
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<center><math>\log_2 ( \log_3 ( \log_5 (\log_ 7 N))) = 11?</math></center>
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<math> \mathrm{(A) \ }1 \qquad \mathrm{(B) \ }2 \qquad \mathrm{(C) \ }3 \qquad \mathrm{(D) \ } 4\qquad \mathrm{(E) \ }7 </math>
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== Solution ==
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Re-writing as exponents, we have <math>\log_3 ( \log_5 (\log_ 7 N)) = 2^{11}</math>, and so forth, such that <math>N = 7^{5^{3^{2^{11}}}}</math>, which only has <math>7</math> as a prime factor <math>\mathbf{(A)}</math>.
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== See also ==
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{{AHSME box|year=1998|num-b=11|num-a=13}}
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[[Category:Introductory Algebra Problems]]
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{{MAA Notice}}

Latest revision as of 13:29, 5 July 2013

Problem

How many different prime numbers are factors of $N$ if

$\log_2 ( \log_3 ( \log_5 (\log_ 7 N))) = 11?$

$\mathrm{(A) \ }1 \qquad \mathrm{(B) \ }2 \qquad \mathrm{(C) \ }3 \qquad \mathrm{(D) \ } 4\qquad \mathrm{(E) \ }7$

Solution

Re-writing as exponents, we have $\log_3 ( \log_5 (\log_ 7 N)) = 2^{11}$, and so forth, such that $N = 7^{5^{3^{2^{11}}}}$, which only has $7$ as a prime factor $\mathbf{(A)}$.

See also

1998 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 11
Followed by
Problem 13
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
All AHSME Problems and Solutions

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