Difference between revisions of "2003 AMC 8 Problems/Problem 5"
AlcumusGuy (talk | contribs) (Created page with "==Problem== If <math>20\%</math> of a number is <math>12</math>, what is <math>30\%</math> of the same number? <math> \textbf{(A)}\ 15\qquad\textbf{(B)}\ 18\qquad\textbf{(C)}\ ...") |
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<math>30\%</math> of <math>n</math> is equal to <math>\frac{3}{10}n = \frac{3}{10}\cdot60 = 3\cdot6 = \boxed{\textbf{(B)}18}</math> | <math>30\%</math> of <math>n</math> is equal to <math>\frac{3}{10}n = \frac{3}{10}\cdot60 = 3\cdot6 = \boxed{\textbf{(B)}18}</math> | ||
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| + | ==See Also== | ||
| + | {{AMC8 box|year=2003|num-b=4|num-a=6}} | ||
| + | {{MAA Notice}} | ||
Latest revision as of 23:46, 4 July 2013
Problem
If 
of a number is 
, what is 
of the same number?
Solution
of a number is equal to 
of that number. Let 
=the number
Multiply both sides by 5
of is equal to 
See Also
| 2003 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 4 |
Followed by Problem 6 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
