Difference between revisions of "1959 AHSME Problems"
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== Problem 1== | == Problem 1== | ||
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== Problem 9== | == Problem 9== | ||
− | A farmer divides his herd of <math>n </math>cows among his four sons so that one son gets one-half the herd, | + | A farmer divides his herd of <math>n</math> cows among his four sons so that one son gets one-half the herd, |
a second son, one-fourth, a third son, one-fifth, and the fourth son, <math>7</math> cows. Then <math>n</math> is: | a second son, one-fourth, a third son, one-fifth, and the fourth son, <math>7</math> cows. Then <math>n</math> is: | ||
+ | |||
<math>\textbf{(A)}\ 80 \qquad\textbf{(B)}\ 100\qquad\textbf{(C)}\ 140\qquad\textbf{(D)}\ 180\qquad\textbf{(E)}\ 240 </math> | <math>\textbf{(A)}\ 80 \qquad\textbf{(B)}\ 100\qquad\textbf{(C)}\ 140\qquad\textbf{(D)}\ 180\qquad\textbf{(E)}\ 240 </math> | ||
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== Problem 10== | == Problem 10== | ||
− | In <math>\triangle ABC</math> with <math>\ | + | In <math>\triangle ABC</math> with <math>\overline{AB}=\overline{AC}=3.6</math>, a point <math>D</math> is taken on <math>AB</math> at a distance <math>1.2</math> from <math>A</math>. |
− | Point <math>D</math> is joined to <math>E</math> in the prolongation of <math>AC</math> so that <math>\triangle AED</math> is equal in area to <math>ABC</math>. Then <math>\ | + | Point <math>D</math> is joined to <math>E</math> in the prolongation of <math>AC</math> so that <math>\triangle AED</math> is equal in area to <math>ABC</math>. Then <math>\overline{AE}</math> is: |
<math>\textbf{(A)}\ 4.8 \qquad\textbf{(B)}\ 5.4\qquad\textbf{(C)}\ 7.2\qquad\textbf{(D)}\ 10.8\qquad\textbf{(E)}\ 12.6 </math> | <math>\textbf{(A)}\ 4.8 \qquad\textbf{(B)}\ 5.4\qquad\textbf{(C)}\ 7.2\qquad\textbf{(D)}\ 10.8\qquad\textbf{(E)}\ 12.6 </math> | ||
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== Problem 21== | == Problem 21== | ||
− | If<math> p</math> is the perimeter of an equilateral <math>\triangle</math> inscribed in a circle, the area of the circle is: | + | If <math>p</math> is the perimeter of an equilateral <math>\triangle</math> inscribed in a circle, the area of the circle is: |
<math>\textbf{(A)}\ \frac{\pi p^2}{3} \qquad\textbf{(B)}\ \frac{\pi p^2}{9}\qquad\textbf{(C)}\ \frac{\pi p^2}{27}\qquad\textbf{(D)}\ \frac{\pi p^2}{81}\qquad\textbf{(E)}\ \frac{\pi p^2\sqrt3}{27} </math> | <math>\textbf{(A)}\ \frac{\pi p^2}{3} \qquad\textbf{(B)}\ \frac{\pi p^2}{9}\qquad\textbf{(C)}\ \frac{\pi p^2}{27}\qquad\textbf{(D)}\ \frac{\pi p^2}{81}\qquad\textbf{(E)}\ \frac{\pi p^2\sqrt3}{27} </math> | ||
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== Problem 24== | == Problem 24== | ||
− | A chemist has m ounces of salt that is <math>m</math>% salt. How many ounces of salt must he add to make a solution that is <math>2m</math>% salt? | + | A chemist has m ounces of salt water that is <math>m</math>% salt. How many ounces of salt must he add to make a solution that is <math>2m</math>% salt? |
<math>\textbf{(A)}\ \frac{m}{100+m} \qquad\textbf{(B)}\ \frac{2m}{100-2m}\qquad\textbf{(C)}\ \frac{m^2}{100-2m}\qquad\textbf{(D)}\ \frac{m^2}{100+2m}\qquad\textbf{(E)}\ \frac{2m}{100+2m}</math> | <math>\textbf{(A)}\ \frac{m}{100+m} \qquad\textbf{(B)}\ \frac{2m}{100-2m}\qquad\textbf{(C)}\ \frac{m^2}{100-2m}\qquad\textbf{(D)}\ \frac{m^2}{100+2m}\qquad\textbf{(E)}\ \frac{2m}{100+2m}</math> | ||
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== Problem 26== | == Problem 26== | ||
− | The base of an isosceles triangle is <math>\sqrt 2</math>. The medians to the | + | The base of an isosceles triangle is <math>\sqrt 2</math>. The medians to the legs intersect each other at right angles. The area of the triangle is: |
<math>\textbf{(A)}\ 1.5 \qquad\textbf{(B)}\ 2\qquad\textbf{(C)}\ 2.5\qquad\textbf{(D)}\ 3.5\qquad\textbf{(E)}\ 4 </math> | <math>\textbf{(A)}\ 1.5 \qquad\textbf{(B)}\ 2\qquad\textbf{(C)}\ 2.5\qquad\textbf{(D)}\ 3.5\qquad\textbf{(E)}\ 4 </math> | ||
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== Problem 27== | == Problem 27== | ||
− | Which one of the following is not true for the equation<math> ix^2-x+2i=0</math>, where <math>i=\sqrt{-1}</math> | + | Which one of the following is not true for the equation <math>ix^2-x+2i=0</math>, where <math>i=\sqrt{-1}</math> |
<math>\textbf{(A)}\ \text{The sum of the roots is 2} \qquad \\ | <math>\textbf{(A)}\ \text{The sum of the roots is 2} \qquad \\ | ||
\textbf{(B)}\ \text{The discriminant is 9}\qquad \\ | \textbf{(B)}\ \text{The discriminant is 9}\qquad \\ | ||
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== Problem 28== | == Problem 28== | ||
− | <math>M</math> are on <math> BC</math> and <math>AB</math>, respectively. The sides of <math>\triangle ABC</math> are <math>a,b | + | In triangle <math>ABC</math>, <math>AL</math> bisects angle <math>A</math>, and <math>CM</math> bisects angle <math>C</math>. Points <math>L</math> and <math>M</math> are on <math>BC</math> and <math>AB</math>, respectively. The sides of <math>\triangle ABC</math> are <math>a</math>, <math>b</math>, and <math>c</math>. Then <math>\frac{AM}{MB}=k\frac{CL}{LB} </math> where <math>k</math> is: |
<math>\textbf{(A)}\ 1 \qquad\textbf{(B)}\ \frac{bc}{a^2}\qquad\textbf{(C)}\ \frac{a^2}{bc}\qquad\textbf{(D)}\ \frac{c}{b}\qquad\textbf{(E)}\ \frac{c}{a} </math> | <math>\textbf{(A)}\ 1 \qquad\textbf{(B)}\ \frac{bc}{a^2}\qquad\textbf{(C)}\ \frac{a^2}{bc}\qquad\textbf{(D)}\ \frac{c}{b}\qquad\textbf{(E)}\ \frac{c}{a} </math> | ||
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== Problem 32== | == Problem 32== | ||
− | The length <math>l</math> of a tangent, drawn from a point <math>A</math> to a circle, is <math>\frac43 </math>of the radius <math>r</math>. The (shortest) distance from A to the circle is: | + | The length <math>l</math> of a tangent, drawn from a point <math>A</math> to a circle, is <math>\frac43 </math> of the radius <math>r</math>. The (shortest) distance from A to the circle is: |
<math>\textbf{(A)}\ \frac{1}{2}r \qquad\textbf{(B)}\ r\qquad\textbf{(C)}\ \frac{1}{2}l\qquad\textbf{(D)}\ \frac23l \qquad\textbf{(E)}\ \text{a value between r and l.} </math> | <math>\textbf{(A)}\ \frac{1}{2}r \qquad\textbf{(B)}\ r\qquad\textbf{(C)}\ \frac{1}{2}l\qquad\textbf{(D)}\ \frac23l \qquad\textbf{(E)}\ \text{a value between r and l.} </math> | ||
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== Problem 34== | == Problem 34== | ||
− | Let the roots of<math>x^2-3x+1=0</math> be <math>r</math> and <math>s</math>. Then the expression <math>r^2+s^2 </math>is: | + | Let the roots of <math>x^2-3x+1=0</math> be <math>r</math> and <math>s</math>. Then the expression <math>r^2 + s^2</math> is: |
<math>\textbf{(A)}\ \text{a positive integer} \qquad\textbf{(B)}\ \text{a positive fraction greater than 1}\qquad\textbf{(C)}\ \text{a positive fraction less than 1}\qquad\textbf{(D)}\ \text{an irrational number}\qquad\textbf{(E)}\ \text{an imaginary number} </math> | <math>\textbf{(A)}\ \text{a positive integer} \qquad\textbf{(B)}\ \text{a positive fraction greater than 1}\qquad\textbf{(C)}\ \text{a positive fraction less than 1}\qquad\textbf{(D)}\ \text{an irrational number}\qquad\textbf{(E)}\ \text{an imaginary number} </math> | ||
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== Problem 35== | == Problem 35== | ||
The symbol <math>\ge</math> means "greater than or equal to"; the symbol <math>\le</math> means "less than or equal to". | The symbol <math>\ge</math> means "greater than or equal to"; the symbol <math>\le</math> means "less than or equal to". | ||
− | In the | + | In the equation <math>(x-m)^2-(x-n)^2=(m-n)^2; m</math> is a fixed positive number, and <math>n</math> is a fixed negative number. The set of values x satisfying the equation is: |
<math>\textbf{(A)}\ x\ge 0 \qquad\textbf{(B)}\ x\le n\qquad\textbf{(C)}\ x=0\qquad\textbf{(D)}\ \text{the set of all real numbers}\qquad\textbf{(E)}\ \text{none of these} </math> | <math>\textbf{(A)}\ x\ge 0 \qquad\textbf{(B)}\ x\le n\qquad\textbf{(C)}\ x=0\qquad\textbf{(D)}\ \text{the set of all real numbers}\qquad\textbf{(E)}\ \text{none of these} </math> | ||
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Let S be the sum of the first nine terms of the sequence <math>x+a, x^2+2a, x^3+3a, \cdots.</math> | Let S be the sum of the first nine terms of the sequence <math>x+a, x^2+2a, x^3+3a, \cdots.</math> | ||
Then S equals: | Then S equals: | ||
− | <math>\textbf{(A)}\ \frac{50a+x+x^8}{x+1} \qquad\textbf{(B)}\ 50a-\frac{x+x^{10}}{x-1}\qquad\textbf{(C)}\ \frac{x^9-1}{x+1}+45a\ | + | <math>\textbf{(A)}\ \frac{50a+x+x^8}{x+1} \qquad\textbf{(B)}\ 50a-\frac{x+x^{10}}{x-1}\qquad\textbf{(C)}\ \frac{x^9-1}{x+1}+45a\qquad\textbf{(D)}\ \frac{x^{10}-x}{x-1}+45a\qquad\textbf{(E)}\ \frac{x^{11}-x}{x-1}+45a </math> |
[[1959 AHSME Problems/Problem 39|Solution]] | [[1959 AHSME Problems/Problem 39|Solution]] | ||
== Problem 40== | == Problem 40== | ||
− | In <math>\triangle ABC</math>, <math>BD</math> is a median. <math>CF</math> intersects <math>BD</math> at <math>E</math> so that <math>\ | + | In <math>\triangle ABC</math>, <math>BD</math> is a median. <math>CF</math> intersects <math>BD</math> at <math>E</math> so that <math>\overline{BE}=\overline{ED}</math>. Point <math>F</math> is on <math>AB</math>. Then, if <math>\overline{BF}=5</math>, |
− | <math>\ | + | <math>\overline{BA}</math> equals: |
<math>\textbf{(A)}\ 10 \qquad\textbf{(B)}\ 12\qquad\textbf{(C)}\ 15\qquad\textbf{(D)}\ 20\qquad\textbf{(E)}\ \text{none of these} </math> | <math>\textbf{(A)}\ 10 \qquad\textbf{(B)}\ 12\qquad\textbf{(C)}\ 15\qquad\textbf{(D)}\ 20\qquad\textbf{(E)}\ \text{none of these} </math> | ||
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== Problem 42== | == Problem 42== | ||
− | Given three positive integers <math>a,b,</math> and <math>c</math>. Their greatest common divisor is <math>D</math>; their least common multiple is <math> | + | Given three positive integers <math>a,b,</math> and <math>c</math>. Their greatest common divisor is <math>D</math>; their least common multiple is <math>M</math>. |
Then, which two of the following statements are true? | Then, which two of the following statements are true? | ||
<math>\text{(1)}\ \text{the product MD cannot be less than abc} \qquad \\ | <math>\text{(1)}\ \text{the product MD cannot be less than abc} \qquad \\ | ||
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== Problem 44== | == Problem 44== | ||
The roots of <math>x^2+bx+c=0</math> are both real and greater than <math>1</math>. Let <math>s=b+c+1</math>. Then <math>s</math>: | The roots of <math>x^2+bx+c=0</math> are both real and greater than <math>1</math>. Let <math>s=b+c+1</math>. Then <math>s</math>: | ||
− | <math>\textbf{(A)}\ \text{may be less than zero}\qquad\textbf{(B)}\ \text{may be equal to zero}\qquad \textbf{(C)} | + | <math>\textbf{(A)}\ \text{may be less than zero}\qquad\textbf{(B)}\ \text{may be equal to zero}\qquad </math> |
+ | |||
+ | <math>\textbf{(C)} \text{ must be greater than zero}\qquad\textbf{(D)}\ \text{must be less than zero}\qquad | ||
\textbf{(E)}\text{ must be between -1 and +1}</math> | \textbf{(E)}\text{ must be between -1 and +1}</math> | ||
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== Problem 45== | == Problem 45== | ||
If <math>\left(\log_3 x\right)\left(\log_x 2x\right)\left( \log_{2x} y\right)=\log_{x}x^2</math>, then <math> y</math> equals: | If <math>\left(\log_3 x\right)\left(\log_x 2x\right)\left( \log_{2x} y\right)=\log_{x}x^2</math>, then <math> y</math> equals: | ||
+ | |||
<math>\textbf{(A)}\ \frac92\qquad\textbf{(B)}\ 9\qquad\textbf{(C)}\ 18\qquad\textbf{(D)}\ 27\qquad\textbf{(E)}\ 81 </math> | <math>\textbf{(A)}\ \frac92\qquad\textbf{(B)}\ 9\qquad\textbf{(C)}\ 18\qquad\textbf{(D)}\ 27\qquad\textbf{(E)}\ 81 </math> | ||
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Assume that the following three statements are true: | Assume that the following three statements are true: | ||
(I). All freshmen are human. (II). All students are human. (III). Some students think. | (I). All freshmen are human. (II). All students are human. (III). Some students think. | ||
+ | |||
Given the following four statements: | Given the following four statements: | ||
+ | |||
<math>\textbf{(1)}\ \text{All freshmen are students.}\qquad \\ | <math>\textbf{(1)}\ \text{All freshmen are students.}\qquad \\ | ||
\textbf{(2)}\ \text{Some humans think.}\qquad \\ | \textbf{(2)}\ \text{Some humans think.}\qquad \\ | ||
\textbf{(3)}\ \text{No freshmen think.}\qquad \\ | \textbf{(3)}\ \text{No freshmen think.}\qquad \\ | ||
\textbf{(4)}\ \text{Some humans who think are not students.}</math> | \textbf{(4)}\ \text{Some humans who think are not students.}</math> | ||
− | Those which are logical consequences of I,II, and III are: | + | |
+ | Those which are logical consequences of I, II, and III are: | ||
+ | |||
<math>\textbf{(A)}\ 2\qquad\textbf{(B)}\ 4\qquad\textbf{(C)}\ 2,3\qquad\textbf{(D)}\ 2,4\qquad\textbf{(E)}\ 1,2 </math> | <math>\textbf{(A)}\ 2\qquad\textbf{(B)}\ 4\qquad\textbf{(C)}\ 2,3\qquad\textbf{(D)}\ 2,4\qquad\textbf{(E)}\ 1,2 </math> | ||
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== Problem 50== | == Problem 50== | ||
A club with <math>x</math> members is organized into four committees in accordance with these two rules: | A club with <math>x</math> members is organized into four committees in accordance with these two rules: | ||
− | |||
− | |||
− | Then < | + | <cmath>\text{(1)}\ \textup{Each member belongs to two and only two committees}\qquad \\ |
+ | \text{(2)}\ \textup{Each pair of committees has one and only one member in common}</cmath> | ||
+ | |||
+ | Then <math>x</math>: | ||
− | < | + | <math>\textbf{(A)} \ \textup{cannot be determined} \qquad \\ |
− | \textbf{(B)} \ \ | + | \textbf{(B)} \ \textup{has a single value between 8 and 16} \qquad \\ |
− | \textbf{(C)} \ \ | + | \textbf{(C)} \ \textup{has two values between 8 and 16} \qquad \\ |
− | \textbf{(D)} \ \ | + | \textbf{(D)} \ \textup{has a single value between 4 and 8} \qquad \\ |
− | \textbf{(E)} \ \ | + | \textbf{(E)} \ \textup{has two values between 4 and 8}</math> |
[[1959 AHSME Problems/Problem 50|Solution]] | [[1959 AHSME Problems/Problem 50|Solution]] | ||
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* [[Mathematics competition resources]] | * [[Mathematics competition resources]] | ||
− | {{AHSME 50p box|year=1959|before=[[1958 AHSME]]|after=[[1960 AHSME]]}} | + | {{AHSME 50p box|year=1959|before=[[1958 AHSME|1958 AHSC]]|after=[[1960 AHSME|1960 AHSC]]}} |
{{MAA Notice}} | {{MAA Notice}} |
Latest revision as of 12:53, 22 July 2024
1959 AHSC (Answer Key) Printable version: | AoPS Resources • PDF | ||
Instructions
| ||
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 • 41 • 42 • 43 • 44 • 45 • 46 • 47 • 48 • 49 • 50 |
Contents
- 1 Problem 1
- 2 Problem 2
- 3 Problem 3
- 4 Problem 4
- 5 Problem 5
- 6 Problem 6
- 7 Problem 7
- 8 Problem 8
- 9 Problem 9
- 10 Problem 10
- 11 Problem 11
- 12 Problem 12
- 13 Problem 13
- 14 Problem 14
- 15 Problem 15
- 16 Problem 16
- 17 Problem 17
- 18 Problem 18
- 19 Problem 19
- 20 Problem 20
- 21 Problem 21
- 22 Problem 22
- 23 Problem 23
- 24 Problem 24
- 25 Problem 25
- 26 Problem 26
- 27 Problem 27
- 28 Problem 28
- 29 Problem 29
- 30 Problem 30
- 31 Problem 31
- 32 Problem 32
- 33 Problem 33
- 34 Problem 34
- 35 Problem 35
- 36 Problem 36
- 37 Problem 37
- 38 Problem 38
- 39 Problem 39
- 40 Problem 40
- 41 Problem 41
- 42 Problem 42
- 43 Problem 43
- 44 Problem 44
- 45 Problem 45
- 46 Problem 46
- 47 Problem 47
- 48 Problem 48
- 49 Problem 49
- 50 Problem 50
- 51 See also
Problem 1
Each edge of a cube is increased by %. The percent of increase of the surface area of the cube is:
Problem 2
Through a point inside the
a line is drawn parallel to the base
, dividing the triangle into two equal areas.
If the altitude to
has a length of
, then the distance from
to
is:
Problem 3
If the diagonals of a quadrilateral are perpendicular to each other, the figure would always be included under the general classification:
Problem 4
If is divided into three parts which are proportional to
the middle part is:
Problem 5
The value of is:
Problem 6
Given the true statement: If a quadrilateral is a square, then it is a rectangle. It follows that, of the converse and the inverse of this true statement is:
Problem 7
The sides of a right triangle are ,
, and
, with
and
both positive. The ratio of
to
is:
Problem 8
The value of can never be less than:
Problem 9
A farmer divides his herd of cows among his four sons so that one son gets one-half the herd,
a second son, one-fourth, a third son, one-fifth, and the fourth son,
cows. Then
is:
Problem 10
In with
, a point
is taken on
at a distance
from
.
Point
is joined to
in the prolongation of
so that
is equal in area to
. Then
is:
Problem 11
The logarithm of to the base
is:
Problem 12
By adding the same constant to a geometric progression results. The common ratio is:
Problem 13
The arithmetic mean (average) of a set of numbers is
. If two numbers, namely,
and
, are discarded, the mean of the remaining set of numbers is:
Problem 14
Given the set whose elements are zero and the even integers, positive and negative.
Of the five operations applied to any pair of elements: (1) addition (2) subtraction
(3) multiplication (4) division (5) finding the arithmetic mean (average), those elements that only yield elements of
are:
Problem 15
In a right triangle the square of the hypotenuse is equal to twice the product of the legs. One of the acute angles of the triangle is:
Problem 16
The expression when simplified is:
Problem 17
If , where
and
are constants, and if
when
, and
when
, then
equals:
Problem 18
The arithmetic mean (average) of the first positive integers is:
Problem 19
With the use of three different weights, namely lb.,
lb., and
lb., how many objects of different weights can be weighed,
if the objects is to be weighed and the given weights may be placed in either pan of the scale?
Problem 20
It is given that varies directly as
and inversely as the square of
, and that
when
and
. Then, when
and
,
equals:
Problem 21
If is the perimeter of an equilateral
inscribed in a circle, the area of the circle is:
Problem 22
The line joining the midpoints of the diagonals of a trapezoid has length . If the longer base is
then the shorter base is:
Problem 23
The set of solutions of the equation consists of
Problem 24
A chemist has m ounces of salt water that is % salt. How many ounces of salt must he add to make a solution that is
% salt?
Problem 25
The symbol means
if
is greater than or equal to zero, and
if a is less than or equal to zero; the symbol
means "less than";
the symbol
means "greater than."
The set of values
satisfying the inequality
consists of all
such that:
Problem 26
The base of an isosceles triangle is . The medians to the legs intersect each other at right angles. The area of the triangle is:
Problem 27
Which one of the following is not true for the equation , where
Problem 28
In triangle ,
bisects angle
, and
bisects angle
. Points
and
are on
and
, respectively. The sides of
are
,
, and
. Then
where
is:
Problem 29
On a examination of questions a student answers correctly
of the first
. Of the remaining questions he answers one third correctly.
All the questions have the same credit. If the student's mark is 50%, how many different values of
can there be?
Problem 30
can run around a circular track in
seconds.
, running in the opposite direction, meets
every
seconds.
What is
's time to run around the track, expressed in seconds?
Problem 31
A square, with an area of , is inscribed in a semicircle. The area of a square that could be inscribed in the entire circle with the same radius, is:
Problem 32
The length of a tangent, drawn from a point
to a circle, is
of the radius
. The (shortest) distance from A to the circle is:
Problem 33
A harmonic progression is a sequence of numbers such that their reciprocals are in arithmetic progression.
Let represent the sum of the first
terms of the harmonic progression; for example
represents the sum of
the first three terms. If the first three terms of a harmonic progression are
, then:
Problem 34
Let the roots of be
and
. Then the expression
is:
Problem 35
The symbol means "greater than or equal to"; the symbol
means "less than or equal to".
In the equation
is a fixed positive number, and
is a fixed negative number. The set of values x satisfying the equation is:
Problem 36
The base of a triangle is , and one side of the base angle is
. The sum of the lengths of the other two sides is
. The shortest side is:
Problem 37
When simplified the product becomes:
Problem 38
If , then
:
Problem 39
Let S be the sum of the first nine terms of the sequence
Then S equals:
Problem 40
In ,
is a median.
intersects
at
so that
. Point
is on
. Then, if
,
equals:
Problem 41
On the same side of a straight line three circles are drawn as follows: a circle with a radius of inches is tangent to the line, the other
two circles are equal, and each is tangent to the line and to the other two circles. The radius of the equal circles is:
Problem 42
Given three positive integers and
. Their greatest common divisor is
; their least common multiple is
.
Then, which two of the following statements are true?
Problem 43
The sides of a triangle are , and
. The diameter of the circumscribed circle is:
Problem 44
The roots of are both real and greater than
. Let
. Then
:
Problem 45
If , then
equals:
Problem 46
A student on vacation for days observed that (1) it rained
times, morning or afternoon (2) when it rained in the afternoon,
it was clear in the morning (3) there were five clear afternoons (4) there were six clear mornings. Then
equals:
Problem 47
Assume that the following three statements are true: (I). All freshmen are human. (II). All students are human. (III). Some students think.
Given the following four statements:
Those which are logical consequences of I, II, and III are:
Problem 48
Given the polynomial , where
is a positive integer or zero, and
is a positive integer.
The remaining
's are integers or zero. Set
. [See example 25 for the meaning of
.]
The number of polynomials with
is:
Problem 49
For the infinite series let
be the (limiting) sum. Then
equals:
Problem 50
A club with members is organized into four committees in accordance with these two rules:
Then :
See also
1959 AHSC (Problems • Answer Key • Resources) | ||
Preceded by 1958 AHSC |
Followed by 1960 AHSC | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 • 41 • 42 • 43 • 44 • 45 • 46 • 47 • 48 • 49 • 50 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.