Difference between revisions of "2015 AMC 10A Problems/Problem 4"
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Pablo, Sofia, and Mia got some candy eggs at a party. Pablo had three times as many eggs as Sofia, and Sofia had twice as many eggs as Mia. Pablo decides to give some of his eggs to Sofia and Mia so that all three will have the same number of eggs. What fraction of his eggs should Pablo give to Sofia? | Pablo, Sofia, and Mia got some candy eggs at a party. Pablo had three times as many eggs as Sofia, and Sofia had twice as many eggs as Mia. Pablo decides to give some of his eggs to Sofia and Mia so that all three will have the same number of eggs. What fraction of his eggs should Pablo give to Sofia? | ||
− | <math> \textbf{(A)}\ \frac{1}{12}\qquad\textbf{(B)}\ \frac{1}{6}\qquad\textbf{(C)}\ \frac{1}{4}\qquad\textbf{(D) | + | <math> \textbf{(A)}\ \frac{1}{12}\qquad\textbf{(B)}\ \frac{1}{6}\qquad\textbf{(C)}\ \frac{1}{4}\qquad\textbf{(D)}\ \frac{1}{3}\qquad\textbf{(E)}\ \frac{1}{2}</math> |
− | ==Solution== | + | ==Solution 1== |
Assign a variable to the number of eggs Mia has, say <math>m</math>. Then, because we are given that Sofia has twice the number of eggs Mia has, Sofia has <math>2m</math> eggs, and Pablo, having three times the number of eggs as Sofia, has <math>6m</math> eggs. | Assign a variable to the number of eggs Mia has, say <math>m</math>. Then, because we are given that Sofia has twice the number of eggs Mia has, Sofia has <math>2m</math> eggs, and Pablo, having three times the number of eggs as Sofia, has <math>6m</math> eggs. | ||
− | For them to all have the same number of eggs, they must each have <math>\frac{m+2m+6m}{3} = 3m</math> eggs. This means Pablo must give <math>2m</math> eggs to Mia and | + | For them to all have the same number of eggs, they must each have <math>\frac{m+2m+6m}{3} = 3m</math> eggs. This means Pablo must give <math>2m</math> eggs to Mia and <math>m</math> eggs to Sofia, so the answer is <math>\frac{m}{6m} = \boxed{\textbf{(B) }\frac{1}{6}}</math> |
+ | |||
+ | ==Solution 2== | ||
+ | Let Mia have <math>1</math> egg. Sofia and Pablo would then have <math>2</math> and <math>6</math> eggs, respectively. If we split the eggs evenly, each would have <math>\frac{1 + 2 + 6}{3} = \frac{9}{3} = 3</math> eggs. Since Sofia needs <math>3 - 2 = 1</math> more egg, Pablo must give her <math>1</math> of his <math>6</math> eggs, or <math>\boxed{\textbf{(B) }\frac{1}{6}}</math> | ||
+ | |||
+ | ==Video Solution (CREATIVE THINKING)== | ||
+ | https://youtu.be/_TR2cVdIRjw | ||
+ | |||
+ | ~Education, the Study of Everything | ||
+ | |||
+ | ==Video Solution== | ||
+ | https://youtu.be/uJ68vr4IA2Q | ||
+ | |||
+ | ~savannahsolver | ||
+ | |||
+ | == Video Solution by OmegaLearn == | ||
+ | https://youtu.be/tKsYSBdeVuw?t=3510 | ||
+ | |||
+ | ~ pi_is_3.14 | ||
+ | |||
+ | ==See Also== | ||
+ | {{AMC10 box|year=2015|ab=A|num-b=3|num-a=5}} | ||
+ | {{MAA Notice}} |
Latest revision as of 21:25, 22 September 2024
Contents
Problem
Pablo, Sofia, and Mia got some candy eggs at a party. Pablo had three times as many eggs as Sofia, and Sofia had twice as many eggs as Mia. Pablo decides to give some of his eggs to Sofia and Mia so that all three will have the same number of eggs. What fraction of his eggs should Pablo give to Sofia?
Solution 1
Assign a variable to the number of eggs Mia has, say . Then, because we are given that Sofia has twice the number of eggs Mia has, Sofia has eggs, and Pablo, having three times the number of eggs as Sofia, has eggs.
For them to all have the same number of eggs, they must each have eggs. This means Pablo must give eggs to Mia and eggs to Sofia, so the answer is
Solution 2
Let Mia have egg. Sofia and Pablo would then have and eggs, respectively. If we split the eggs evenly, each would have eggs. Since Sofia needs more egg, Pablo must give her of his eggs, or
Video Solution (CREATIVE THINKING)
https://youtu.be/_TR2cVdIRjw
~Education, the Study of Everything
Video Solution
~savannahsolver
Video Solution by OmegaLearn
https://youtu.be/tKsYSBdeVuw?t=3510
~ pi_is_3.14
See Also
2015 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 3 |
Followed by Problem 5 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
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