Difference between revisions of "1954 AHSME Problems/Problem 7"
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== Solution == | == Solution == | ||
Since she saved <math>\textdollar{2.50}</math> and spent <math>\textdollar{25}</math>, the original price of the dress was <math>\textdollar{27.50}</math>. The percent saved can be modeled as <math>27.5x=2.5</math>, so the answer is <math>x=\frac{2.5}{27.5}</math> or <math>\frac{1}{11}</math>, approximately <math>9\% \implies \textbf{(B)}</math> | Since she saved <math>\textdollar{2.50}</math> and spent <math>\textdollar{25}</math>, the original price of the dress was <math>\textdollar{27.50}</math>. The percent saved can be modeled as <math>27.5x=2.5</math>, so the answer is <math>x=\frac{2.5}{27.5}</math> or <math>\frac{1}{11}</math>, approximately <math>9\% \implies \textbf{(B)}</math> | ||
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| + | {{AHSME 50p box|year=1954|num-b=6|num-a=8}} | ||
| + | {{MAA Notice}} | ||
Latest revision as of 16:49, 15 April 2017
Problem 7
A housewife saved 
in buying a dress on sale. If she spent 
for the dress, she saved about:
Solution
Since she saved and spent , the original price of the dress was 
. The percent saved can be modeled as 
, so the answer is 
or 
, approximately 
| 1954 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 6 |
Followed by Problem 8 | |
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| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
