Difference between revisions of "2002 AMC 12A Problems/Problem 17"
(→Solution) |
(→Solution) |
||
| Line 21: | Line 21: | ||
We can indeed create a set of primes with this sum, for example the following sets work: <math>\{ 41, 67, 89, 2, 3, 5 \}</math> or <math>\{ 43, 61, 89, 2, 5, 7 \}</math>. | We can indeed create a set of primes with this sum, for example the following sets work: <math>\{ 41, 67, 89, 2, 3, 5 \}</math> or <math>\{ 43, 61, 89, 2, 5, 7 \}</math>. | ||
| − | Thus the answer is <math>207\implies \boxed{(B)}</math>. | + | Thus the answer is <math>207\implies \boxed{\mathrm{(B)}}</math>. |
== See Also == | == See Also == | ||
Revision as of 07:24, 8 November 2019
Problem
Several sets of prime numbers, such as 
use each of the nine nonzero digits exactly once. What is the smallest possible sum such a set of primes could have?
Solution
Neither of the digits 
, 
, and 
can be a units digit of a prime. Therefore the sum of the set is at least 
.
We can indeed create a set of primes with this sum, for example the following sets work: 
or 
.
Thus the answer is 
.
See Also
| 2002 AMC 12A (Problems • Answer Key • Resources) | |
| Preceded by Problem 16 |
Followed by Problem 18 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
