Difference between revisions of "2003 AIME II Problems/Problem 11"
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== Problem == | == Problem == | ||
| + | Triangle <math>ABC</math> is a right triangle with <math>AC = 7,</math> <math>BC = 24,</math> and right angle at <math>C.</math> Point <math>M</math> is the midpoint of <math>AB,</math> and <math>D</math> is on the same side of line <math>AB</math> as <math>C</math> so that <math>AD = BD = 15.</math> Given that the area of triangle <math>CDM</math> may be expressed as <math>\frac {m\sqrt {n}}{p},</math> where <math>m,</math> <math>n,</math> and <math>p</math> are positive integers, <math>m</math> and <math>p</math> are relatively prime, and <math>n</math> is not divisible by the square of any prime, find <math>m + n + p.</math> | ||
== Solution == | == Solution == | ||
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== See also == | == See also == | ||
| − | + | {{AIME box|year=2003|n=II|num-b=10|num-a=12}} | |
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Revision as of 13:40, 21 November 2007
Problem
Triangle 
is a right triangle with 
and right angle at 
Point 
is the midpoint of 
and 
is on the same side of line 
as 
so that 
Given that the area of triangle 
may be expressed as 
where 
and 
are positive integers, 
and are relatively prime, and 
is not divisible by the square of any prime, find 
Solution
This problem needs a solution. If you have a solution for it, please help us out by adding it.
See also
| 2003 AIME II (Problems • Answer Key • Resources) | ||
| Preceded by Problem 10 |
Followed by Problem 12 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
| All AIME Problems and Solutions | ||
