Difference between revisions of "1986 AIME Problems/Problem 8"
m (→See also: box) |
m |
||
Line 1: | Line 1: | ||
== Problem == | == Problem == | ||
− | + | Let <math>\displaystyle S</math> be the sum of the base <math>\displaystyle 10</math> logarithms of all the proper divisors of <math>\displaystyle 1000000</math>. What is the integer nearest to <math>\displaystyle S</math>? | |
== Solution == | == Solution == | ||
+ | {{solution}} | ||
== See also == | == See also == |
Revision as of 19:04, 10 February 2007
Problem
Let be the sum of the base logarithms of all the proper divisors of . What is the integer nearest to ?
Solution
This problem needs a solution. If you have a solution for it, please help us out by adding it.
See also
1986 AIME (Problems • Answer Key • Resources) | ||
Preceded by Problem 7 |
Followed by Problem 9 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
All AIME Problems and Solutions |