Difference between revisions of "2018 AMC 8 Problems/Problem 24"
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==Note== | ==Note== | ||
− | In the 2008 AMC 10A,[[2008 AMC 10A Problems/Problem 21 | + | In the 2008 AMC 10A,[[2008 AMC 10A Problems/Problem 21 Question 23] was nearly identical to this question, except that in this question you have to look for the square of the area, not the actual area. |
==Video Solution== | ==Video Solution== |
Revision as of 15:51, 28 October 2020
Problem 24
In the cube with opposite vertices
and
and
are the midpoints of segments
and
respectively. Let
be the ratio of the area of the cross-section
to the area of one of the faces of the cube. What is
Note
In the 2008 AMC 10A,[[2008 AMC 10A Problems/Problem 21 Question 23] was nearly identical to this question, except that in this question you have to look for the square of the area, not the actual area.
Video Solution
https://www.youtube.com/watch?v=04pV_rZw8bg - Happytwin
Video Solution
https://www.youtube.com/watch?v=ji9_6XNxyIc ~ MathEx
See Also
2018 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 23 |
Followed by Problem 25 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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