Difference between revisions of "2007 AMC 8 Problems/Problem 3"

Revision as of 11:22, 16 August 2021

What is the sum of the two smallest prime factors of $250$ ?

$\mathrm{(A)}\ 2 \qquad\mathrm{(B)}\ 5 \qquad\mathrm{(C)}\ 7 \qquad\mathrm{(D)}\ 10 \qquad\mathrm{(E)}\ 12$

The prime factorization of $250$ is $2 \cdot 5^3$ . The smallest two are $2$ and $5$ . $2+5 = \boxed{\text{(C) }7}$ .

2007 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 2	Followed by Problem 4
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

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 == Solution ==
-The prime factorization of 250 is 2*5^3 The smallest two are 2 and 5 2+5 =C:7
+The prime factorization of <math>250</math> is <math>2 \cdot 5^3</math>. The smallest two are <math>2</math> and <math>5</math>. <math>2+5 = \boxed{\text{(C) }7}</math>.
 ==See Also==
 {{AMC8 box|year=2007|num-b=2|num-a=4}}
 {{MAA Notice}}