Difference between revisions of "2007 AMC 12A Problems/Problem 2"
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== Solution == | == Solution == | ||
| − | The water has volume <math>100 \cdot 40 \cdot 40=160000</math>. The brick has volume 8000. The water and the brick combined have a volume of 168000. The water rises | + | The water has volume <math>100 \cdot 40 \cdot 40=160000</math>. The brick has volume 8000. The water and the brick combined have a volume of 168000. The water rises <math>\frac{168000}{4000}-\frac{160000}{4000}=42-40=2</math> cm. |
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== See also == | == See also == | ||
Revision as of 10:41, 9 September 2007
Problem
An aquarium has a rectangular base that measures 100 cm by 40 cm and has a height of 50 cm. It is filled with water to a height of 40 cm. A brick with a rectangular base that measures 40 cm by 20 cm and a height of 10 cm is placed in the aquarium. By how many centimeters does the water rise?
Solution
The water has volume 
. The brick has volume 8000. The water and the brick combined have a volume of 168000. The water rises 
cm.
See also
| 2007 AMC 12A (Problems • Answer Key • Resources) | |
| Preceded by Problem 1 |
Followed by Problem 3 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
