Difference between revisions of "2022 AMC 8 Problems/Problem 12"
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<math>\textbf{(A)} ~\dfrac{1}{16}\qquad\textbf{(B)} ~\dfrac{1}{8}\qquad\textbf{(C)} ~\dfrac{1}{4}\qquad\textbf{(D)} ~\dfrac{3}{8}\qquad\textbf{(E)} ~\dfrac{1}{2}</math> | <math>\textbf{(A)} ~\dfrac{1}{16}\qquad\textbf{(B)} ~\dfrac{1}{8}\qquad\textbf{(C)} ~\dfrac{1}{4}\qquad\textbf{(D)} ~\dfrac{3}{8}\qquad\textbf{(E)} ~\dfrac{1}{2}</math> | ||
− | ==Solution== | + | ==Solution 1== |
First, we realize that there are a total of <math>16</math> possibilities. Now, we list all of them that can be spun. This includes <math>64</math> and <math>81</math>. Then, our answer is <math>\frac{2}{16}=\boxed{\textbf{(B) }\dfrac{1}{8}}</math>. | First, we realize that there are a total of <math>16</math> possibilities. Now, we list all of them that can be spun. This includes <math>64</math> and <math>81</math>. Then, our answer is <math>\frac{2}{16}=\boxed{\textbf{(B) }\dfrac{1}{8}}</math>. | ||
~MathFun1000 | ~MathFun1000 | ||
+ | |||
+ | ==Solution 2== | ||
+ | |||
+ | There are <math>4 \cdot 4 = 16</math> total possibilities of <math>N</math>. We know <math>N=10A+B</math>, which <math>A</math> is a number from spinner <math>A</math>, and <math>B</math> is a number from spinner <math>B</math>. Also, notice that there are no perfect squares in the <math>50</math>s or <math>70</math>s, so only <math>4-2=2</math> values of N work, namely <math>64</math> and <math>81</math>. Hence, <math>\frac{2}{16}=\boxed{\textbf{(B) }\dfrac{1}{8}}</math>. | ||
+ | |||
+ | ~MrThinker | ||
==Video Solution== | ==Video Solution== |
Revision as of 09:24, 7 October 2022
Problem
The arrows on the two spinners shown below are spun. Let the number equal times the number on Spinner , added to the number on Spinner . What is the probability that is a perfect square number?
Solution 1
First, we realize that there are a total of possibilities. Now, we list all of them that can be spun. This includes and . Then, our answer is .
~MathFun1000
Solution 2
There are total possibilities of . We know , which is a number from spinner , and is a number from spinner . Also, notice that there are no perfect squares in the s or s, so only values of N work, namely and . Hence, .
~MrThinker
Video Solution
https://youtu.be/Ij9pAy6tQSg?t=1008
~Interstigation
See Also
2022 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 11 |
Followed by Problem 13 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.