Difference between revisions of "2002 AMC 12A Problems/Problem 1"
(→Solution) |
|||
| Line 1: | Line 1: | ||
| − | |||
== Problem == | == Problem == | ||
Compute the sum of all the roots of | Compute the sum of all the roots of | ||
| Line 14: | Line 13: | ||
The sum of the roots is therefore | The sum of the roots is therefore | ||
| − | <math>5-\dfrac{3}{2}=\dfrac{7}{2} \Rightarrow \mathrm {( | + | <math>5-\dfrac{3}{2}=\dfrac{7}{2} \Rightarrow \mathrm {(A)}</math> |
== See also == | == See also == | ||
{{AMC12 box|year=2002|ab=A|before=First Question|num-a=2}} | {{AMC12 box|year=2002|ab=A|before=First Question|num-a=2}} | ||
Revision as of 14:25, 24 December 2007
Problem
Compute the sum of all the roots of
Solution
That is equal to 
We can divide out by 4 to get
The sum of the roots is therefore
See also
| 2002 AMC 12A (Problems • Answer Key • Resources) | |
| Preceded by First Question |
Followed by Problem 2 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
