Difference between revisions of "2002 AIME I Problems/Problem 10"

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== See also ==
 
== See also ==
* [[2002 AIME I Problems/Problem 9| Previous problem]]
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{{AIME box|year=2002|n=I|num-b=9|num-a=11}}
 
 
* [[2002 AIME I Problems/Problem 11| Next problem]]
 
 
 
* [[2002 AIME I Problems]]
 

Revision as of 14:14, 25 November 2007

Problem

In the diagram below, angle $ABC$ is a right angle. Point $D$ is on $\overline{BC}$, and $\overline{AD}$ bisects angle $CAB$. Points $E$ and $F$ are on $\overline{AB}$ and $\overline{AC}$, respectively, so that $AE=3$ and $AF=10$. Given that $EB=9$ and $FC=27$, find the integer closest to the area of quadrilateral $DCFG$.

AIME 2002I Problem 10.png

Solution

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See also

2002 AIME I (ProblemsAnswer KeyResources)
Preceded by
Problem 9
Followed by
Problem 11
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All AIME Problems and Solutions