Difference between revisions of "2016 AMC 10B Problems/Problem 1"
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==Solution 2== | ==Solution 2== | ||
− | Substituting <math>\frac{1}{2}</math> for <math>a</math> in <math>\frac{\frac{1}{a}\cdot(2+\frac{1}{2})}{a}</math> gives us <math>\boxed{\textbf{(D) }10}</math>. | + | Substituting <math>\frac{1}{2}</math> for <math>a</math> in <math>\frac{\frac{1}{a}\cdot(2+\frac{1}{2})}{a}</math> gives us <math>\boxed{\textbf{(D) }10}</math>. |
==Video Solution (CREATIVE THINKING)== | ==Video Solution (CREATIVE THINKING)== |
Latest revision as of 20:39, 6 August 2024
Contents
Problem
What is the value of when
?
Solution
Factorizing the numerator, then becomes
which is equal to
which is
.
Solution 2
Substituting for
in
gives us
.
Video Solution (CREATIVE THINKING)
~Education, the Study of Everything
Video Solution
~savannahsolver
See Also
2016 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by - |
Followed by Problem 2 | |
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All AMC 10 Problems and Solutions |
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