Difference between revisions of "2024 AMC 10A Problems/Problem 3"

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== Solution ==
 
== Solution ==
Recall that <math>2</math> is the only even prime.
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Let the requested sum be <math>S.</math> Recall that <math>2</math> is the only even (and the smallest) prime, so <math>S</math> is odd. It follows that the five distinct primes are all odd.
  
Let the requested sum be <math>S.</math> Clearly, <math>S</math> is odd. It follows that the five distinct primes are all odd.  
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The first few odd primes are <math>3,5,7,11,13,17,19,\ldots,</math> so <math>S>3+5+7+11+13=39,</math> as <math>39</math> is a composite.
  
 
==See also==
 
==See also==
 
{{AMC10 box|year=2024|ab=A|before=2|num-a=4}}
 
{{AMC10 box|year=2024|ab=A|before=2|num-a=4}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 15:31, 8 November 2024

Problem

What is the sum of the digits of the smallest prime that can be written as a sum of $5$ distinct primes?

$\textbf{(A) }5\qquad\textbf{(B) }7\qquad\textbf{(C) }9\qquad\textbf{(D) }10\qquad\textbf{(E) }13$

Solution

Let the requested sum be $S.$ Recall that $2$ is the only even (and the smallest) prime, so $S$ is odd. It follows that the five distinct primes are all odd.

The first few odd primes are $3,5,7,11,13,17,19,\ldots,$ so $S>3+5+7+11+13=39,$ as $39$ is a composite.

See also

2024 AMC 10A (ProblemsAnswer KeyResources)
Preceded by
2
Followed by
Problem 4
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

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