Difference between revisions of "1989 AJHSME Problems/Problem 5"
5849206328x (talk | contribs) (New page: ==Problem== <math>-15+9\times (6\div 3) =</math> <math>\text{(A)}\ -48 \qquad \text{(B)}\ -12 \qquad \text{(C)}\ -3 \qquad \text{(D)}\ 3 \qquad \text{(E)}\ 12</math> ==Solution== We us...) |
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{{AJHSME box|year=1989|num-b=4|num-a=6}} | {{AJHSME box|year=1989|num-b=4|num-a=6}} | ||
[[Category:Introductory Algebra Problems]] | [[Category:Introductory Algebra Problems]] | ||
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Latest revision as of 22:57, 4 July 2013
Problem
Solution
We use the order of operations here to get
See Also
1989 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 4 |
Followed by Problem 6 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.