Difference between revisions of "1989 AJHSME Problems/Problem 6"

(New page: ==Problem== If the markings on the number line are equally spaced, what is the number <math>\text{y}</math>? <asy> draw((-4,0)--(26,0),Arrows); for(int a=0; a<6; ++a) { draw((4a,-...)
 
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{{AJHSME box|year=1989|num-b=5|num-a=7}}
 
{{AJHSME box|year=1989|num-b=5|num-a=7}}
 
[[Category:Introductory Algebra Problems]]
 
[[Category:Introductory Algebra Problems]]
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{{MAA Notice}}

Revision as of 22:57, 4 July 2013

Problem

If the markings on the number line are equally spaced, what is the number $\text{y}$?

[asy] draw((-4,0)--(26,0),Arrows); for(int a=0; a<6; ++a)  {   draw((4a,-1)--(4a,1));  } label("0",(0,-1),S); label("20",(20,-1),S); label("y",(12,-1),S); [/asy]

$\text{(A)}\ 3 \qquad \text{(B)}\ 10 \qquad \text{(C)}\ 12 \qquad \text{(D)}\ 15 \qquad \text{(E)}\ 16$

Solution

Five steps are taken to get from $0$ to $20$. Each step is of equal size, so each step is $4$. Three steps are taken from $0$ to $y$, so $y=3\times 4=12\rightarrow \boxed{\text{C}}$.

See Also

1989 AJHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 5
Followed by
Problem 7
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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