Difference between revisions of "1999 AMC 8 Problems/Problem 2"
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This makes them <math>\frac{1}{6}</math>th of a circle apart, and <math>\frac{1}{6}\cdot360^{\circ}=\boxed{60\text{ (C)}}</math>. | This makes them <math>\frac{1}{6}</math>th of a circle apart, and <math>\frac{1}{6}\cdot360^{\circ}=\boxed{60\text{ (C)}}</math>. | ||
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+ | ==See Also== | ||
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+ | {{AMC8 box|year=1999|num-b=1|num-a=3}} |
Revision as of 15:07, 12 June 2011
Problem
What is the degree measure of the smaller angle formed by the hands of a clock at 10 o'clock?
Solution
At , the hour hand will be on the while the minute hand on the .
This makes them th of a circle apart, and .
See Also
1999 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 3 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |