Difference between revisions of "2003 AMC 8 Problems/Problem 11"
Math Kirby (talk | contribs) (Created page with "== Problem == Business is a little slow at Lou's Fine Shoes, so Lou decides to have a sale. On Friday, Lou increases all of Thursday's prices by <math> 10% </math>. Over the week...") |
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== Solution == | == Solution == | ||
On Friday, the shoes would cost <math> 40 \cdot 1.1= 44 </math> dollars. Then on Monday, the shoes would cost <math> 44- \frac{44}{10}=44-4.4=\boxed{\textbf{(B)}\ 39.60} </math>. | On Friday, the shoes would cost <math> 40 \cdot 1.1= 44 </math> dollars. Then on Monday, the shoes would cost <math> 44- \frac{44}{10}=44-4.4=\boxed{\textbf{(B)}\ 39.60} </math>. | ||
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+ | {{AMC8 box|year=2003|num-b=10|num-a=12}} |
Revision as of 09:01, 25 November 2011
Problem
Business is a little slow at Lou's Fine Shoes, so Lou decides to have a sale. On Friday, Lou increases all of Thursday's prices by $10%$ (Error compiling LaTeX. Unknown error_msg). Over the weekend, Lou advertises the sale: Ten percent off the listed price. Sale starts Monday." How much does a pair of shoes cost on Monday that cost dollars on Thursday?
Solution
On Friday, the shoes would cost dollars. Then on Monday, the shoes would cost .
2003 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 10 |
Followed by Problem 12 | |
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All AJHSME/AMC 8 Problems and Solutions |