Difference between revisions of "1950 AHSME Problems/Problem 19"
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The number of men is inversely proportional to the number of days the job takes. Thus, if <math> m </math> men can do a job in <math> d </math> days, we have that it will take <math> md </math> days for <math> 1 </math> man to do the job. Thus, <math> m + r </math> men can do the job in <math> \frac{md}{m+r} </math> days and our is <math> \textbf{(C)}. </math> | The number of men is inversely proportional to the number of days the job takes. Thus, if <math> m </math> men can do a job in <math> d </math> days, we have that it will take <math> md </math> days for <math> 1 </math> man to do the job. Thus, <math> m + r </math> men can do the job in <math> \frac{md}{m+r} </math> days and our is <math> \textbf{(C)}. </math> | ||
+ | ==See Also== | ||
{{AHSME box|year=1950|num-b=18|num-a=20}} | {{AHSME box|year=1950|num-b=18|num-a=20}} | ||
+ | |||
+ | [[Category:Introductory Algebra Problems]] |
Revision as of 14:23, 17 April 2012
Problem
If men can do a job in
days, then
men can do the job in:
Solution
The number of men is inversely proportional to the number of days the job takes. Thus, if men can do a job in
days, we have that it will take
days for
man to do the job. Thus,
men can do the job in
days and our is
See Also
1950 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 18 |
Followed by Problem 20 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |