Difference between revisions of "1999 AMC 8 Problems/Problem 2"
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for(int i = 0; i < 12; ++i) | for(int i = 0; i < 12; ++i) | ||
Revision as of 13:56, 22 December 2021
Problem
What is the degree measure of the smaller angle formed by the hands of a clock at 10 o'clock?
draw(circle((0,0),2))
dot((0,0));
for(int i = 0; i < 12; ++i)
{
dot(2*dir(30*i));
}
label("$3$",2*dir(0),W);
label("$2$",2*dir(30),WSW);
label("$1$",2*dir(60),SSW);
label("$12$",2*dir(90),S);
label("$11$",2*dir(120),SSE);
label("$10$",2*dir(150),ESE);
label("$9$",2*dir(180),E);
label("$8$",2*dir(210),ENE);
label("$7$",2*dir(240),NNE);
label("$6$",2*dir(270),N);
label("$5$",2*dir(300),NNW);
label("$4$",2*dir(330),WNW);
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Solution
At 
, the hour hand will be on the 
while the minute hand on the 
.
This makes them 
th of a circle apart, and 
.
See Also
| 1999 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 3 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
