Difference between revisions of "1980 AHSME Problems/Problem 3"
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Cross multiplying gets | Cross multiplying gets | ||
| − | <math>6x-3y=2x+2y\\4x=5y\\ \dfrac{x}{y}=\dfrac{5}{4}\\ \boxed{(E)}</math> | + | <math>6x-3y=2x+2y\\4x=5y\\ \dfrac{x}{y}=\dfrac{5}{4}\\ \boxed{(E)}</math> |
| − | + | ||
| + | Support Me | ||
== See also == | == See also == | ||
{{AHSME box|year=1980|num-b=2|num-a=4}} | {{AHSME box|year=1980|num-b=2|num-a=4}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Latest revision as of 11:06, 2 September 2024
Problem
If the ratio of 
to 
is 
, what is the ratio of 
to 
?
Solution
Cross multiplying gets
Support Me
See also
| 1980 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 2 |
Followed by Problem 4 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
