Difference between revisions of "2014 AMC 10B Problems/Problem 4"
TheCrafter (talk | contribs) (Added solution) |
Royalreter1 (talk | contribs) (→Problem 4) |
||
| Line 1: | Line 1: | ||
| − | ==Problem | + | ==Problem== |
Susie pays for <math>4</math> muffins and <math>3</math> bananas. Calvin spends twice as much paying for <math>2</math> muffins and <math>16</math> bananas. A muffin is how many times as expensive as a banana? | Susie pays for <math>4</math> muffins and <math>3</math> bananas. Calvin spends twice as much paying for <math>2</math> muffins and <math>16</math> bananas. A muffin is how many times as expensive as a banana? | ||
Revision as of 14:00, 20 February 2014
Problem
Susie pays for 
muffins and 
bananas. Calvin spends twice as much paying for 
muffins and 
bananas. A muffin is how many times as expensive as a banana?
Solution
Let 
be the cost of a muffin and 
be the cost of a banana. From the given information, ![\[2m+16b=2(4m+3b)=8m+6b\Rightarrow 10b=6m\Rightarrow m=\frac{10}{6}b=\boxed{\frac{5}{3}}b\]](http://latex.artofproblemsolving.com/c/3/f/c3f08f233c37981f87386812825c78b0e7d1a37b.png)
See Also
| 2014 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by Problem 3 |
Followed by Problem 5 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
