Difference between revisions of "1970 AHSME Problems/Problem 10"
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| − | Let <math>F=.48181\cdots</math> be an infinite repeating decimal with the digits <math>8</math> and | + | Let <math>F=.48181\cdots</math> be an infinite repeating decimal with the digits <math>8</math> and <math>1</math> repeating. When <math>F</math> is written as a fraction in lowest terms, the denominator exceeds the numerator by |
<math>\text{(A) } 13\quad | <math>\text{(A) } 13\quad | ||
Revision as of 17:35, 1 October 2014
Problem
Let 
be an infinite repeating decimal with the digits 
and 
repeating. When 
is written as a fraction in lowest terms, the denominator exceeds the numerator by
Solution
See also
| 1970 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 9 |
Followed by Problem 11 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
