Difference between revisions of "1970 AHSME Problems/Problem 29"
(Created page with "== Problem == It is now between 10:00 and 11:00 o'clock, and six minutes from now, the minute hand of a watch will be exactly opposite the place where the hour hand was three mi...") |
(→Solution) |
||
Line 11: | Line 11: | ||
== Solution == | == Solution == | ||
<math>\fbox{D}</math> | <math>\fbox{D}</math> | ||
+ | 50 + (m-3)/12 = 30 + (m+6) | ||
+ | = 10hours + m = 10: 15 | ||
== See also == | == See also == |
Revision as of 08:31, 8 January 2021
Problem
It is now between 10:00 and 11:00 o'clock, and six minutes from now, the minute hand of a watch will be exactly opposite the place where the hour hand was three minutes ago. What is the exact time now?
Solution
50 + (m-3)/12 = 30 + (m+6) = 10hours + m = 10: 15
See also
1970 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 28 |
Followed by Problem 30 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.