Difference between revisions of "2016 AMC 12B Problems/Problem 2"
(→Solution) |
m (→Solution) |
||
Line 10: | Line 10: | ||
==Solution== | ==Solution== | ||
+ | By: dragonfly | ||
+ | |||
Since the harmonic mean is <math>2</math> times their product divided by their sum, we get the equation | Since the harmonic mean is <math>2</math> times their product divided by their sum, we get the equation | ||
Revision as of 21:33, 21 February 2016
Problem
The harmonic mean of two numbers can be calculated as twice their product divided by their sum. The harmonic mean of and is closest to which integer?
Solution
By: dragonfly
Since the harmonic mean is times their product divided by their sum, we get the equation
which is then
which is finally closest to .
See Also
2016 AMC 12B (Problems • Answer Key • Resources) | |
Preceded by Problem 1 |
Followed by Problem 3 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.