Difference between revisions of "2018 AMC 8 Problems/Problem 5"
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==Solution== | ==Solution== | ||
− | Rearranging the terms, we get <math>(1-2)+(3-4)+(5-6)+...(2017-2018)+2019</math>, and our answer is <math>-1009+2019=\boxed{1010}, \textbf{(E)}</math> | + | Rearranging the terms, we get <math>(1-2)+(3-4)+(5-6)+...(2017-2018)+2019</math>, and our answer is <math>-1009+2019=\boxed{1010}, \textbf{(E)}</math>- ProMathdunk123 |
Revision as of 12:51, 21 November 2018
Problem 5
What is the value of ?
Solution
Rearranging the terms, we get , and our answer is - ProMathdunk123
2018 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 4 |
Followed by Problem 6 | |
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All AJHSME/AMC 8 Problems and Solutions |