Difference between revisions of "2018 AMC 8 Problems/Problem 16"
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==Solution== | ==Solution== | ||
| − | There are <math>2!</math> ways to arrange the Arabic books within their block, <math>4!</math> for Spanish, and <math>5!</math> for the two blocks and three books, for a product of <math>2!4!5!=\boxed{ | + | There are <math>2!</math> ways to arrange the Arabic books within their block, <math>4!</math> for Spanish, and <math>5!</math> for the two blocks and three books, for a product of <math>2!4!5!=\boxed{\textbf{(C) }5760}</math>. |
| + | ==See Also== | ||
{{AMC8 box|year=2018|num-b=15|num-a=17}} | {{AMC8 box|year=2018|num-b=15|num-a=17}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 18:44, 21 November 2018
Problem 16
Professor Chang has nine different language books lined up on a bookshelf: two Arabic, three German, and four Spanish. How many ways are there to arrange the nine books on the shelf keeping the Arabic books together and keeping the Spanish books together?
Solution
There are 
ways to arrange the Arabic books within their block, 
for Spanish, and 
for the two blocks and three books, for a product of 
.
See Also
| 2018 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 15 |
Followed by Problem 17 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
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