Difference between revisions of "2020 AMC 12A Problems/Problem 6"
Line 68: | Line 68: | ||
==See Also== | ==See Also== | ||
− | + | {{AMC12 box|year=2020|ab=A|num-b=5|num-a=7}} | |
− | {{AMC12 box|year=2020|ab=A|num-b= | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 14:59, 1 February 2020
Problem 6
In the plane figure shown below, of the unit squares have been shaded. What is the least number of additional unit squares that must be shaded so that the resulting figure has two lines of symmetry?
Solution
The two lines of symmetry must be horizontally and vertically through the middle. We can then fill the boxes in like so:
where the light gray boxes are the ones we have filled. Counting these, we get total boxes. ~ciceronii
See Also
2020 AMC 12A (Problems • Answer Key • Resources) | |
Preceded by Problem 5 |
Followed by Problem 7 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.