Difference between revisions of "2006 AMC 12A Problems/Problem 12"
m (→Solution: should use show preview button more often... anyway, more typos) |
m (→See also) |
||
Line 12: | Line 12: | ||
* [[2006 AMC 12A Problems]] | * [[2006 AMC 12A Problems]] | ||
− | {{ | + | {{AMC12 box|year=2006|ab=A|num-b=11|num-a=13}} |
[[Category:Introductory Algebra Problems]] | [[Category:Introductory Algebra Problems]] | ||
[[Category:Introductory Geometry Problems]] | [[Category:Introductory Geometry Problems]] |
Revision as of 18:19, 2 February 2007
Problem
An image is supposed to go here. You can help us out by creating one and editing it in. Thanks.
A number of linked rings, each 1 cm thick, are hanging on a peg. The top ring has an outside diameter of 20 cm. The outside diameter of each of the outer rings is 1 cm less than that of the ring above it. The bottom ring has an outside diameter of 3 cm. What is the distance, in cm, from the top of the top ring to the bottom of the bottom ring?
Solution
The sum of the consecutively increasing integers from 3 to 20 is . However, the 17 intersections between the rings must also be subtracted, so we get .
See also
2006 AMC 12A (Problems • Answer Key • Resources) | |
Preceded by Problem 11 |
Followed by Problem 13 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |