Difference between revisions of "1955 AHSME Problems/Problem 16"

(Created page with "== Problem 16== The value of <math>\frac{3}{a+b}</math> when <math>a=4</math> and <math>b=-4</math> is: <math> \textbf{(A)}\ 3\qquad\textbf{(B)}\ \frac{3}{8}\qquad\textbf{(...")
 
 
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== Solution ==
 
== Solution ==
 
As the denominator is <math>4 - (-4) = 0</math>, the value of the fraction <math>\frac{3}{4 - (-4)}</math> is <math>\textbf{(E)}\ \text{meaningless}</math>
 
As the denominator is <math>4 - (-4) = 0</math>, the value of the fraction <math>\frac{3}{4 - (-4)}</math> is <math>\textbf{(E)}\ \text{meaningless}</math>
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==See Also==
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{{AHSME 50p box|year=1955|num-b=15|num-a=17}}
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{{MAA Notice}}

Latest revision as of 13:19, 23 July 2020

Problem 16

The value of $\frac{3}{a+b}$ when $a=4$ and $b=-4$ is:

$\textbf{(A)}\ 3\qquad\textbf{(B)}\ \frac{3}{8}\qquad\textbf{(C)}\ 0\qquad\textbf{(D)}\ \text{any finite number}\qquad\textbf{(E)}\ \text{meaningless}$

Solution

As the denominator is $4 - (-4) = 0$, the value of the fraction $\frac{3}{4 - (-4)}$ is $\textbf{(E)}\ \text{meaningless}$

See Also

1955 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 15
Followed by
Problem 17
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All AHSME Problems and Solutions


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