Difference between revisions of "2006 AMC 10A Problems/Problem 15"
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== Solution == | == Solution == | ||
{{solution}} | {{solution}} | ||
| + | *please note that this is this solution has not been confirmed but is only my own solution to the problem. | ||
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| + | We know that Odell and Kershaw meet after they run a total of one circle together. Odell runs at 250m/min for 30 mins in a circle of length of 100pi, and that Kershaw runs at 300m/min for 30 mins in a circle 120pi in length. Both Odell and Kershaw run 23.8 laps around their respective circles. together they run 47.6 laps. Therefore, they meet a total of 47 times. | ||
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| + | (D) 47 | ||
== See Also == | == See Also == | ||
*[[2006 AMC 10A Problems]] | *[[2006 AMC 10A Problems]] | ||
Revision as of 20:37, 14 February 2007
Problem
Odell and Kershaw run for 30 minutes on a circular track. Odell runs clockwise at 250 m/min and uses the inner lane with a radius of 50 meters. Kershaw runs counterclockwise at 300 m/min and uses the outer lane with a radius of 60 meters, starting on the same radial line as Odell. How many times after the start do they pass each other?
Solution
This problem needs a solution. If you have a solution for it, please help us out by adding it.
- please note that this is this solution has not been confirmed but is only my own solution to the problem.
We know that Odell and Kershaw meet after they run a total of one circle together. Odell runs at 250m/min for 30 mins in a circle of length of 100pi, and that Kershaw runs at 300m/min for 30 mins in a circle 120pi in length. Both Odell and Kershaw run 23.8 laps around their respective circles. together they run 47.6 laps. Therefore, they meet a total of 47 times.
(D) 47
