Difference between revisions of "2018 AMC 8 Problems/Problem 1"

(Solution 4)
(Solution 1)
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You can see that since the ratios of real building's heights to the model building's height is 1:20. We also know that the U.S Capitol is 289 feet in real life so to find the height of the model, we divide by 20. That gives us 14.45 which rounds to 14. So the answer is <math>\boxed{\textbf{(A)}14}</math>. That is how I did it ~avamarora.
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You can see that since the ratios of real building's heights to the model building's height is 1:20. We also know that the U.S Capitol is 289 feet in real life so to find the height of the model, we divide by 20. That gives us 14.45 which rounds to 14. So the answer is <math>\boxed{\textbf{(A)}14}</math>. ~avamarora.
  
 
==Solution 2==
 
==Solution 2==

Revision as of 15:43, 28 November 2020

Problem 1

An amusement park has a collection of scale models, with a ratio $1: 20$, of buildings and other sights from around the country. The height of the United States Capitol is 289 feet. What is the height in feet of its duplicate to the nearest whole number?

$\textbf{(A) }14\qquad\textbf{(B) }15\qquad\textbf{(C) }16\qquad\textbf{(D) }18\qquad\textbf{(E) }20$

Solution 1

You can see that since the ratios of real building's heights to the model building's height is 1:20. We also know that the U.S Capitol is 289 feet in real life so to find the height of the model, we divide by 20. That gives us 14.45 which rounds to 14. So the answer is $\boxed{\textbf{(A)}14}$. ~avamarora.

Solution 2

You can just do $\frac{289}{20}$ and round your answer to get $\boxed{\textbf{(A)}14}$. It is basically Solution 1 without the ratio calculation, which might not be necessary.

Solution 3

We know that $20 \cdot 14 = 280 ,$ and that $20 \cdot 15 = 300 .$ These are the multiples of $20$ around $289 ,$ and the closest one of those is $280.$ Therefore, the answer is $\dfrac {280} {14} = \boxed{\textbf{(A) }14} .$

See also

2018 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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