Difference between revisions of "1996 AIME Problems/Problem 13"

(See also)
(Problem)
Line 1: Line 1:
 
== Problem ==
 
== Problem ==
{{empty}}
+
In triangle <math>ABC</math>, <math>AB=\sqrt{30}</math>, <math>AC=\sqrt{6}</math>, and <math>BC=\sqrt{15}</math>. There is a point <math>D</math> for which <math>\overline{AD}</math> bisects <math>\overline{BC}</math>, and <math>\angle ADB</math> is a right angle. The ratio
 +
 
 +
<cmath>\dfrac{Area(\triangle ADB)}{Area(\triangle ABC)}</cmath>
 +
 
 +
can be written in the form <math>\dfrac{m}{n}</math>, where <math>m</math> and <math>n</math> are relatively prime positive integers. Find <math>m+n</math>
 +
 
 
== Solution ==
 
== Solution ==
 
{{solution}}
 
{{solution}}

Revision as of 15:22, 24 September 2007

Problem

In triangle $ABC$, $AB=\sqrt{30}$, $AC=\sqrt{6}$, and $BC=\sqrt{15}$. There is a point $D$ for which $\overline{AD}$ bisects $\overline{BC}$, and $\angle ADB$ is a right angle. The ratio

\[\dfrac{Area(\triangle ADB)}{Area(\triangle ABC)}\]

can be written in the form $\dfrac{m}{n}$, where $m$ and $n$ are relatively prime positive integers. Find $m+n$

Solution

This problem needs a solution. If you have a solution for it, please help us out by adding it.

See also

1996 AIME (ProblemsAnswer KeyResources)
Preceded by
Problem 12
Followed by
Problem 14
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
All AIME Problems and Solutions