Difference between revisions of "2022 AMC 8 Problems/Problem 1"
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<math>\textbf{(A) } 10 \qquad \textbf{(B) } 12 \qquad \textbf{(C) } 13 \qquad \textbf{(D) } 14 \qquad \textbf{(E) } 15</math> | <math>\textbf{(A) } 10 \qquad \textbf{(B) } 12 \qquad \textbf{(C) } 13 \qquad \textbf{(D) } 14 \qquad \textbf{(E) } 15</math> | ||
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+ | ==Solution== | ||
+ | Note that the given symbol can be split into <math>5</math> diamonds. Each of the diamonds are made of <math>4</math> triangles, so each of the diamonds has an area of <math>0.5 \cdot 4 = 2</math>. Hence, our answer is <math>2 \cdot 5 = \boxed{\textbf{(A) }10}</math>. | ||
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+ | <i>pog</i> | ||
+ | |||
+ | ==See also== | ||
+ | {{AMC8 box|year=2022|before=First Problem|num-a=2}} | ||
+ | {{MAA Notice}} |
Revision as of 09:23, 28 January 2022
Problem
The Math Team designed a logo shaped like a multiplication symbol, shown below on a grid of 1-inch squares. What is the area of the logo in square inches?
Solution
Note that the given symbol can be split into diamonds. Each of the diamonds are made of triangles, so each of the diamonds has an area of . Hence, our answer is .
pog
See also
2022 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by First Problem |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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