Difference between revisions of "2022 AMC 8 Problems/Problem 4"
MRENTHUSIASM (talk | contribs) |
MRENTHUSIASM (talk | contribs) m |
||
Line 40: | Line 40: | ||
size(3cm); | size(3cm); | ||
draw((-1,0)--(1,0)); draw((0,-1)--(0,1)); label(rotate(270)*"$\textbf{\textsf{M}}$",(0.6,0.25)); | draw((-1,0)--(1,0)); draw((0,-1)--(0,1)); label(rotate(270)*"$\textbf{\textsf{M}}$",(0.6,0.25)); | ||
− | draw((-0.8,-0.8)--(0.8,0.8),linewidth(1.1)); | + | draw((-0.8,-0.8)--(0.8,0.8),linewidth(1.1)); |
</asy> | </asy> | ||
When <b>M</b> is then reflected over the line <math>p,</math> we obtain the following diagram: | When <b>M</b> is then reflected over the line <math>p,</math> we obtain the following diagram: | ||
Line 48: | Line 48: | ||
size(3cm); | size(3cm); | ||
draw((-1,0)--(1,0)); draw((0,-1)--(0,1)); label(rotate(270)*"$\textbf{\textsf{M}}$",(0.6,-0.25)); | draw((-1,0)--(1,0)); draw((0,-1)--(0,1)); label(rotate(270)*"$\textbf{\textsf{M}}$",(0.6,-0.25)); | ||
− | draw((-0.8,-0.8)--(0.8,0.8),linewidth(1.1)); | + | draw((-0.8,-0.8)--(0.8,0.8),linewidth(1.1)); |
</asy> | </asy> | ||
Therefore, the answer is <math>\boxed{\textbf{(E)}}.</math> | Therefore, the answer is <math>\boxed{\textbf{(E)}}.</math> |
Revision as of 13:04, 28 January 2022
Problem
The letter M in the figure below is first reflected over the line and then reflected over the line . What is the resulting image?
Solution
When M is first reflected over the line we obtain the following diagram: When M is then reflected over the line we obtain the following diagram: Therefore, the answer is
~MRENTHUSIASM
See Also
2022 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 3 |
Followed by Problem 5 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.