Difference between revisions of "2022 AMC 8 Problems/Problem 12"
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First, we realize that there are a total of <math>16</math> possibilities. Now, we list all of them that can be spun. This includes <math>64</math> and <math>81</math>. Then, our answer is <math>\frac{2}{16}=\boxed{\textbf{(B) }\dfrac{1}{8}}</math>. | First, we realize that there are a total of <math>16</math> possibilities. Now, we list all of them that can be spun. This includes <math>64</math> and <math>81</math>. Then, our answer is <math>\frac{2}{16}=\boxed{\textbf{(B) }\dfrac{1}{8}}</math>. | ||
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+ | ~MathFun1000 | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2022|num-b=10|num-a=12}} | {{AMC8 box|year=2022|num-b=10|num-a=12}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 17:17, 28 January 2022
Problem
The arrows on the two spinners shown below are spun. Let the number equal 10 times the number on Spinner A, added to the number on Spinner B. What is the probability that N is a perfect square number?
Solution
First, we realize that there are a total of possibilities. Now, we list all of them that can be spun. This includes and . Then, our answer is .
~MathFun1000
See Also
2022 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 10 |
Followed by Problem 12 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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